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- 1. Md Zahidul Islam lecturerat MIU Welcome to all of you
- 2. 8085 Microprocessor: Architecture &Support Components
- 3. 3 Microprocessor Architecture Themicroprocessor can be programmed to perform functions on given data by writing specific instructions into its memory. The microprocessor reads one instruction at a time, matches it with its instruction set, and performs the data manipulation specified. The result is either stored back into memory or displayed on an output device.
- 5. Pinout Diagram of8085 A 40-pin IC Six groups of signals Address Bus Data Bus Control and Status pins Power Supply & frequency signals Externally initiated Signals Serial I/O ports U7 8085 36 1 2 5 6 9 8 7 10 11 29 33 39 35 12 13 14 15 16 17 18 19 21 22 23 24 25 26 27 28 30 31 32 34 3 374 38 40 20 RST-IN X1 X2 SID TRAP RST 5.5 RST 6.5 RST 7.5 INTR INTA S0 S1 HOLD READY AD0 AD1 AD2 AD3 AD4 AD5 AD6 AD7 A8 A9 A10 A11 A12 A13 A14 A15 ALE WR RD IO/M RST-OT CLKOSOD HLDA VCC VSS
- 6. Logic Pinout of8085 DataBus AddressBus U8 8085 36 1 2 5 6 9 8 7 10 11 29 33 39 35 12 13 14 15 16 17 18 19 21 22 23 24 25 26 27 28 30 31 32 34 3 37 4 38 40 20 RST-IN X1 X2 SID TRAP RST 5.5 RST 6.5 RST 7.5 INTR INTA S0 S1 HOLD READY AD0 AD1 AD2 AD3 AD4 AD5 AD6 AD7 A8 A9 A10 A11 A12 A13 A14 A15 ALE WR RD IO/M RST-OT CLKO SOD HLDA VCC VSS Control & Status Control & Status Externally initiated signals Serial I/O ports Power Supply & frequency
- 7. 7 The 8085 Architecture The 8085 uses three separate busses to perform its operations The address bus. The data bus. The control bus.
- 8. 8 The Address Bus 16 bits wide (A0 A1…A15) Therefore, the 8085 can access locations with numbers from 0 to 65,536. Or, the 8085 can access a total of 64K addresses. “Unidirectional”. Information flows out of the microprocessor and into the memory or peripherals. When the 8085 wants to access a peripheral or a memory location, it places the 16-bit address on the address bus and then sends
- 9. 9 The Data Bus 8 bits wide (D0 D1…D7) “Bi-directional”. Information flows both ways between the microprocessor and memory or I/O. The 8085 uses the data bus to transfer the binary information. Since the data bus has 8-bits only, then the 8085 can manipulate data 8 bits at-a-time only.
- 10. 10 The Control Bus There is no real control bus. Instead, the control bus is made up of a number of single bit control signals.
- 11. 8085 Operations MicroprocessorInitiated Operations Internal Operations Peripheral/Externally Initiated Operations
- 12. Microprocessor Initiated Operations Memory Read Memory Write I/O Read I/O Write
- 13. 13 Microprocessor Initiated Operations Theseare operations that the microprocessor itself starts. These are usually one of 4 operations: Memory Read Memory Write I/O Read (Get data from an input device) I/O write (Send data to an output device) Interrupt signal
- 14. 14 Microprocessor Initiated Operations It is important to note that the microprocessor treats memory and I/O devices the same way. The communication process between the microprocessor and peripheral devices consist of the following three steps: Identify the address. Transfer the binary information. Provide the right timing signals.
- 15. 15 The Read Operation To read the contents of a memory location, the following steps take place: The microprocessor places the 16-bit address of the memory location on the address bus. The microprocessor activates a control signal called “memory read” which enables the memory chip. The memory decodes the address and identifies the right location. The memory places the contents on the data bus. The microprocessor reads the value of the data bus after a certain amount of time.
- 16. 16 Internal Data Operations The 8085 can perform a number of internal operations. Such as: storing data, Arithmetic & Logic operations, Testing for condition, etc. To perform these operations, the microprocessor needs an internal architecture similar to the following: Accumulator Flags B C D E H L Program Counter Stack Pointer DataAddress 816
- 17. Internal Operations Store8-bit data Perform Arithmetic and Logic Operations Test for conditions Sequence the execution of instructions Store/Retrieve data from stack during execution
- 18. 18 The Internal Architecture We have already discussed the general purpose registers, the Accumulator, and the flags. The Program Counter (PC) This is a register that is used to control the sequencing of the execution of instructions. This register always holds the address of the next instruction. Since it holds an address, it must be 16 bits wide.
- 19. 19 The Internal Architecture The Stack pointer The stack pointer is also a 16-bit register that is used to point into memory. The memory this register points to is a special area called the stack. The stack is an area of memory used to hold data that will be retreived soon. The stack is usually accessed in a Last In First Out (LIFO) fashion.
- 20. Peripheral/Externally Initiated Operations Reset Interrupt Ready Hold
- 21. 21 Externally Initiated Operations External devices can initiate (start) one of the 4 following operations: Reset All operations are stopped and the program counter is reset to 0000. Interrupt The microprocessor’s operations are interrupted and the microprocessor executes what is called a “service routine”. This routine “handles” the interrupt, (perform the necessary operations). Then the microprocessor returns to its previous operations and continues.
- 22. 22 Externally Initiated Operations Ready The 8085 has a pin called RDY. This pin is used by external devices to stop the 8085 until they catch up. As long as the RDY pin is low, the 8085 will be in a wait state. Hold The 8085 has a pin called HOLD. This pin is used by external devices to gain control of the busses. When the HOLD signal is activated by an external device, the 8085 stops executing instructions and stops using the busses.
- 23. Architecture of 8085 Power Supply – a +5V DC power supply Maximum clock frequency of 3MHz 8-bit general purpose microprocessor 16-bit Address Bus Capable of addressing 64K of memory
- 24.
- 25. Architecture 0f 8085Cont… ALU Timing and Control Unit General Purpose Registers Program Status word Program Counter Stack Pointer Instruction Register and Decoder Interrupt Control Serial I/O Control Address Bus Data Bus
- 26. Architecture 0f 8085Cont… Arithmetic Logic Unit (ALU) 8085 has 8-bit ALU Performs arithmetic & Logic operations on data Timing & Control Unit Generates timing and control signals General Purpose Registers 8-bit registers (B,C,D,E,H,L) 16-bit register pairs (BC, DE, HL,PSW)
- 27. Architecture 0f 8085Cont… Program Status Word (PSW) Accumulator and Flag Register can be combined as a register pair called PSW Instruction Register and Decoder Instruction fetched from memory is stored in Instruction register (8-bit register) Decoder decodes the instruction and directs the Timing & Control Unit accordingly
- 28. Architecture 0f 8085Cont… Interrupt Control 8085 has 5 interrupt signals INTR – general purpose interrupt RST 5.5 Restart Interrupts RST 6.5 RST 7.5 TRAP – non-maskable interrupt The interrupts listed above are in increasing order of priority
- 29. Architecture 0f 8085Cont… Serial I/O Control 8085 has two signals for serial communication SID – Serial Input Data SOD – Serial Output Data
- 30. Architecture 0f 8085Cont…
- 31. Architecture 0f 8085Cont… Address Bus Used to address memory & I/O devices 8085 has a 16-bit address bus A15 A14 A13 A12 A11 A10 A9 A8 AD7 AD6 AD5 AD4 AD3 AD2 AD1 AD0 Lower-order AddressHigher-order Address Data Bus Used to transfer instructions and data 8085 has a 8-bit data bus Data Bus
- 32. 8085 Communication withMemory Involves the following three steps 1. Identify the memory location (with address) 2. Generate Timing & Control signals 3. Data transfer takes place
- 33. Example: Memory ReadOperation 1 2 3
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- 36. Demultiplexing Address/Data Bus 8085 identifies a memory location with its 16 address lines, (AD0 to AD7) & (A8 to A15) 8085 performs data transfer using its data lines, AD0 to AD7 Lower order address bus & Data bus are multiplexed on same lines i.e. AD0 to AD7. Demultiplexing refers to separating Address & Data signals for read/write operations
- 37. Need for Demultiplexing… 8085Memory A8-A15 20H AD0-AD7 05H RD 4FH 2005H
- 38. The 16-bitaddress of the memory location must be applied to the memory chip for the whole duration of the memory read/write operation. Lower-order address needs to be saved before microprocessor uses it for data transfer Need for Demultiplexing…
- 40. 8085 Interfacing withMemory chips 8085 Memory Interface Memory Chip Address Data Control Address Data Control
- 41. 8085 Interfacing withMemory chips 8085 Memory Interface Memory Chip AD0-AD7 Control A0 – A7 Data 74LS373 A8-A15 A8-A15 ALE
- 42. 8085 Interfacing withMemory chips 8085 Memory Interface Program Memory AD0-AD7 IO/M A0 – A7 Data 74LS373 A8-A15 A8-A15 ALE RD RD CS
- 43. U2 74LS373 3 4 7 8 13 14 17 18 111 2 5 6 9 12 15 16 19 D0 D1 D2 D3 D4 D5 D6 D7 OCG Q0 Q1 Q2 Q3 Q4 Q5 Q6 Q7 U1 8085 36 1 2 5 6 9 8 7 10 11 29 33 39 35 12 13 14 15 16 17 18 19 21 22 23 24 25 26 27 28 30 31 32 34 3 37 4 38 RST-IN X1 X2 SID TRAP RST 5.5 RST 6.5 RST7.5 INTR INTA S0 S1 HOLD READY AD0 AD1 AD2 AD3 AD4 AD5 AD6 AD7 A8 A9 A10 A11 A12 A13 A14 A15 ALE WR RD IO/M RST-OT CLKO SOD HLDA U3 27C512A 10 9 8 7 6 5 4 3 25 24 21 23 2 26 20 22 27 1 11 12 13 15 16 17 18 19 A0 A1 A2 A3 A4 A5 A6 A7 A8 A9 A10 A11 A12 A13 CE OE/VPP A14 A15 O0 O1 O2 O3 O4 O5 O6 O7
- 44. Memory Mapping 8085has 16-bit Address Bus The complete address space is thus given by the range of addresses 0000H – FFFFH The range of addresses allocated to a memory device is known as its memory map
- 45. Memory map: 64Kmemory device Address lines required: 16 (A0 – A15) Memory map: 0000H - FFFFH Memory map: 32K memory device Address lines required: 15 (A0 – A14) Memory map: depends on how address line A15 is connected
- 46. U1 8085 36 1 2 5 6 9 8 7 10 11 29 33 39 35 12 13 14 15 16 17 18 19 21 22 23 24 25 26 27 28 30 31 32 34 3 37 4 38 RST-IN X1 X2 SID TRAP RST 5.5 RST 6.5 RST7.5 INTR INTA S0 S1 HOLD READY AD0 AD1 AD2 AD3 AD4 AD5 AD6 AD7 A8 A9 A10 A11 A12 A13 A14 A15 ALE WR RD IO/M RST-OT CLKO SOD HLDA U2 74LS373 3 4 7 8 13 14 17 18 111 2 5 6 9 12 15 16 19 D0 D1 D2 D3 D4 D5 D6 D7 OCG Q0 Q1 Q2 Q3 Q4 Q5 Q6 Q7 U4 27C256 10 9 8 7 6 5 4 3 25 24 21 23 2 26 27 20 22 1 11 12 13 15 16 17 18 19 A0 A1 A2 A3 A4 A5 A6 A7 A8 A9 A10 A11 A12 A13 A14 CE OE VPP O0 O1 O2 O3 O4 O5 O6 O7 U5A 74LS32 1 2 3 Memory device is selected only if IO/M = 0 & A15 = 0
- 47. So thememory map is 0 0 0 0 A11 to A0A15 A14 A13 A12 0…. 0 0 = 0000H 0 1 1 1 A11 to A0A15 A14 A13 A12 1…. 111 = 7FFFH to
- 48. Interfacing I/O devices with8085 Peripheral-mapped I/O & Memory-mapped I/O
- 49. Interfacing I/O deviceswith 8085 8085 I/O Interface I/O Devices Memory Interface Memory Devices System Bus
- 50. Techniques for I/OInterfacing Memory-mapped I/O Peripheral-mapped I/O
- 51. Memory-mapped I/O 8085uses its 16-bit address bus to identify a memory location Memory address space: 0000H to FFFFH 8085 needs to identify I/O devices also I/O devices can be interfaced using addresses from memory space 8085 treats such an I/O device as a memory location This is called Memory-mapped I/O
- 52. Peripheral-mapped I/O 8085has a separate 8-bit addressing scheme for I/O devices I/O address space: 00H to FFH This is called Peripheral-mapped I/O or I/O-mapped I/O
- 53. 8085 Communication withI/O devices Involves the following three steps 1. Identify the I/O device (with address) 2. Generate Timing & Control signals 3. Data transfer takes place 8085 communicates with a I/O device only if there is a Program Instruction to do so
- 54. 1.Identify the I/Odevice (with address) 1. Memory-mapped I/O (16-bit address) 2. Peripheral-mapped I/O (8-bit address)
- 55. 2.Generate Timing &Control Signals Memory-mapped I/O Reading Input: IO/M = 0, RD = 0 Write to Output: IO/M = 0, WR = 0 Peripheral-mapped I/O Reading Input: IO/M = 1, RD = 0 Write to Output: IO/M = 1, WR = 0 3. Data transfer takes place
- 56. 8085 Communication withI/O devices Involves the following three steps Identify the I/O device (with address) Generate Timing & Control signals Data transfer takes place 8085 communicates with a I/O device only if there is a Program Instruction to do so
- 57. Peripheral I/O Instructions IN Instruction Inputs data from input device into the accumulator It is a 2-byte instruction Format: IN 8-bit port address Example: IN 01H
- 58. OUT Instruction Outputs the contents of accumulator to an output device It is a 2-byte instruction Format: OUT 8-bit port address Example: OUT 02H
- 59. ----------Example Program---------- WAPto read a number from input port (port address 01H) and display it on ASCII display connected to output port (port address 02H) IN 01H ;reads data value 03H (example)into ;accumulator, A = 03H MVI B, 30H;loads register B with 30H ADD B ;A = 33H, ASCII code for 3 OUT 02H ;display 3 on ASCII display
- 60. Memory-mapped I/O Instructions I/O devices are identified by 16-bit addresses 8085 communicates with an I/O device as if it were one of the memory locations Memory related instructions are used For e.g. LDA, STA LDA 8000H Loads A with data read from input device with 16-bit address 8000H STA 8001H Stores (Outputs) contents of A to output device with 16-bit address 8001H
- 61. ----------Example Program---------- WAPto read a number from input port (port address 8000H) and display it on ASCII display connected to output port (port address 8001H) LDA 8000H;reads data value 03H (example)into ;accumulator, A = 03H MVI B, 30H;loads register B with 30H ADD B ;A = 33H, ASCII code for 3 STA 8001H;display 3 on ASCII display