Interpolating variables in a Parse::RecDescent regex

Question

I'm working on a Parse::RecDescent grammar to read a given human-readable set of rules and then spit out a file that is much easier for a computer to read.

One of the tokens is a list of "keywords"; about 26 different keywords. These may change over time, and may be referenced by multiple pieces of code. Consequently, I want to store the keyword-y things in a data file and load them in.

A feature of Parse::RecDescent is the ability to interpolate variables in regexes, and I would like to use it.

I wrote up some code as a proof of concept:

@arr = ("foo", "bar", "frank", "jim");


$data = <<SOMEDATA;
This is some data with the word foo in it
SOMEDATA

$arrstr = join("|", @arr);

if($data =~ /($arrstr)/)
{
    print "Matched $1\n";
}
else
{
    print "Failed to match\n";
}

This worked correctly. When I moved to my main program to implement it, I wrote:

{
    my $myerror = open(FILE, "data.txt") or die("Failed to open data");
    my @data_arr = <FILE>;
    close FILE;
    my $dataarrstr = join("|", @data_arr);

}
#many rules having nothing to do with the data array are here...

event : /($dataarrstr)/
    { $return = $item[1]; }
    |

And at this point, I received this error from P::RD: ERROR (line 18): Invalid event: Was expecting /($dataarrstr)/.

I don't know why. Does anyone have any ideas that would serve to help me out here?

edit: This is not a scoping issue- I've tried that. I've also tried the m{...} syntax.

Paul Nathan · Accepted Answer · 2009-06-09 18:33:16Z

3

After perusing documentation and a very similar question over at http://perlmonks.org/?node_id=384098, I worked out this solution.

event :/\w+/
    {
        $return = ::is_valid_event($item[1]);
    }
    | <error>

Outside the grammar -

#This manages the problem of not being able to interpolate the variable 
#in the grammar action
sub is_valid_event {
    my $word = shift @_;
    if($word =~ /$::data_str/)
    {
        return $word;
    }
    else
    {
        return undef;
    }
}

answered Jun 9, 2009 at 18:33

Paul Nathan

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