In the example seen on superfastpython.com, the size of a shared memory segment to be used to support a 1-dimensional numpy array is calculated as the number of elements multiplied by the data type size.
We know that the size parameter given to the SharedMemory constructor is a minimum. Thus, in many cases, the actual size may be larger than that specified - and that's fine.
But what if the specified size is an exact multiple of the underlying memory page size?
Consider this:
import numpy as np
from multiprocessing.shared_memory import SharedMemory
n = 2048
s = n * np.dtype(np.double).itemsize
shm = SharedMemory(create=True, size=s)
try:
assert s == shm.size
a = np.ndarray((n,), dtype=np.double, buffer=shm.buf)
a.fill(0.0)
finally:
shm.close()
shm.unlink()
In this case (Python 13.3.0 on macOS 15.0.1) the value of s is 16,384 which happens to be a precise multiple of the underlying page size and therefore shm.size is equal to s
Maybe I don't know enough about numpy but I would have imagined that the ndarray would need more space for internal / management structures.
Can someone please explain why this works and why there's no apparent need to allow extra space in the shared memory segment?
