Using Python3, I have the following for loop that outputs a year followed by a day number as one figure. I want to be able to be able to convert this into a proper date. Please see below the code and what I am trying to achieve.
from datetime import datetime
import os
import rasterio
for filename in sorted(os.listdir(output_dir)):
f = os.path.join(output_dir, filename)
# checking if it is a file
if os.path.isfile(f):
#print(filename)
with rasterio.open(f) as clipped:
import re
x_title = re.findall('\d+', filename)[0]
date_object = datetime.strptime(x_title, "%Y%j")
print(date_object)
When I run this code I get something like 2022-04-05 00:00:00 for the variable date_object which is close to what I want but there are two issues. First, there are the hours, minutes and seconds values showing up which I do not need, and second, I would then like to convert the date into a proper date such as "April 5 2022" rather than "2022-04-05".
Perhaps my lack of knowledge of the datetime module is the root cause but at this point I could use a hand. Thanks again.
datetimeyou can format it how you like. I added a second duplicate which presents some options.date = datetime(year, 1, 1) + timedelta(days)and thendatetime.strftime(date,"%d %B %Y").%Bis for full month name. Here are all the codes.