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I am trying to understand PIC18 code in a format like TRISB &= 0b11100000. What is the order the individual RB pins appear in? i.e. is this register setting RB0-RB2 as input, or RB5-RB7 as input?

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Reset to default
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After using TRISB &= 0b11100000, RB5-RB7 will keep their state and RB0-RB4 will be cleared - set to outputs.

Usually clearing bits is done with TRISB &= ~(0b00011111) for 'clarity'

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in the code TRISB &= 0b11100000, the binary value sets the direction of the lowest pins, RB0-RB2, as outputs, and the highest, RB5-RB7, as inputs.

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Actually, it doesn't touch RB5-RB7, it leaves them as they are. Because it's a &=, not a = operation.
Indeed, it doesn't change the states of ` RB5-RB7; it only clears bits RB0 to RB4 to make them outputs while leaving RB5-RB7` in their current states.

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