how can i print zero at the first of output [duplicate]

Question

#include <stdio.h>

int main(void) {
  int Phone_number1,Phone_number2,Phone_number3 ; 
  printf("Enter phone number [(xxx) xxx-xxxx]: ");
  scanf("(%d) %d-%d" , &Phone_number1 , &Phone_number2 , &Phone_number3);
  
   printf("you entered: %d.%d.%d ",Phone_number1,Phone_number2,Phone_number3 );
  return 0;
}

Enter phone number [(xxx) xxx-xxxx]: (010) 7568-5230 // this was my input

you entered: 10.7568.5230 // this was my out put

display user phone number //my code

but i wanted to print like this 010.7568.5230

i don't find it out where is zero at the first of output

i think zero is same role as white space during computing so the first zero couldn't show up in my output

Try %03d.%04d.%04d instead of %d.%d.%d when you printf. — wohlstad
– wohlstad, Commented Mar 1, 2023 at 5:37

Nitin Jadhav · Accepted Answer · 2023-03-01 06:06:31Z

printf in C has formatting rules. Click_here for reference in regards to understanding printf in detail. Here I'll briefly outline with respect to your question.

"%03d %04d" is a formatting in printf will specify how your phone number will be printed.

d stands for decimal integer (not double!), so it says there will be no floating point or anything like that, just a regular integer.
3 shows how many digits will the printed number have. More precisely, the number will take at least 3 digits: 010 will be 10 but adding 3 will place zero at the start. (similar is case for %04d
0 before 3 shows that leading spaces should be replaced by zeroes.

Check similar explanation for sprintf.

Modified code:

#include <stdio.h>

int main(void) {
  int Phone_number1,Phone_number2,Phone_number3 ; 
  printf("Enter phone number [(xxx) xxx-xxxx]: ");
  scanf("(%d) %d-%d" , &Phone_number1 , &Phone_number2 , &Phone_number3);
  printf("you entered: %03d.%04d.%04d ",Phone_number1,Phone_number2,Phone_number3 );
  return 0;
}

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