I know this is a bit on nonsense but I need to get the closest number out of 2 arrays or:
const myarr = [[12, 42], [12, 56], [30, 54]]
console.log(colsest_out_of_closest(myarr, [12, 50]))
2 Answers
It looks like you want to find the smallest difference between both the min and the max.
const closest_out_of_closest = (arr, criteria) => {
const [min, max] = criteria;
let result, prevDiff = Number.MAX_VALUE;
arr.forEach((item) => {
const [localMin, localMax] = item;
const diff = Math.abs(localMin - min) + Math.abs(localMax - max);
if (diff < prevDiff) {
prevDiff = diff;
result = item;
}
});
return result;
};
const myarr = [[12, 42], [12, 56], [30, 54]];
console.log(closest_out_of_closest(myarr, [12, 50])); // [12, 56]Here is a reducer version that is less bytes, but still readable:
const closestRange = (arr, [min, max]) =>
arr.reduce((acc, [lMin, lMax]) =>
(diff => diff < acc.prev ? { result: [lMin, lMax], prev: diff } : acc)
(Math.abs(lMin - min) + Math.abs(lMax - max)),
{ result: null, prev: Number.MAX_VALUE }).result;
console.log(closestRange([[12, 42], [12, 56], [30, 54]], [12, 50])); // [12, 56]
Comments
You could check the absolute delta.
const
getClosest = (a, b, t) => Math.abs(t - a) < Math.abs(t - b) ? a : b,
getClosestPair = (target, array) => values.reduce((a, b) =>
[0, 1].map(i => getClosest(a[i], b[i], target[i]))
),
values = [[12, 42], [12, 56], [30, 54]],
closest = getClosestPair([12, 50], values);
console.log(closest);
[12, 56]is closest to the first number, but[30, 54]is closest to the second number.[12, 56][12,56]the expected output? Please shared what you have tried and explain the logic behind the expected output.