I have a table indexed on a text column, and I want all my queries to return results ordered by name without any performance hit. Table has around 1 million rows if it matters.
Table -
CREATE TABLE table (Name text)
Index -
CREATE INDEX "NameIndex" ON "Files" (
"Name" COLLATE nocase ASC
);
Query 1 -
select * from table where Name like "%a%"
Query plan, as expected a full scan -
SCAN TABLE table
Time -
Result: 179202 rows returned in 53ms
Query 2, now using order by to read from index -
select * from table where Name like "%a%" order by Name collate nocase
Query plan, scan using index -
SCAN TABLE table USING INDEX NameIndex
Time -
Result: 179202 rows returned in 672ms
Used DB Browser for SQLite to get the information above, with default Pragmas.
I'd assume scanning the index would be as performant as scanning the table, is it not the case or am I doing something wrong?
Another interesting thing I noticed, that may be relevant -
Query 3 -
select * from table where Name like "a%"
Result: 23026 rows returned in 9ms
Query 4 -
select * from table where name like "a%" order by name collate nocase
Result: 23026 rows returned in 101ms
And both has them same query plan -
SEARCH TABLE table USING INDEX NameIndex (Name>? AND Name<?)
Is this expected? I'd assume the performance be the same if the plan was the same.
Thanks!
EDIT - The reason the query is slower was because I used select * and not select name, causing SQLite to go between the table and the index.
The solution was to use clustered index, thanks @Tomalak for helping me find it -
create table mytable (a text, b text, primary key (a,b)) without rowid
The table will be ordered by default using a + b combination, meaning that full scan queries will be much faster (now 90ms).