Convert decimal point number to integer - PowerShell

Question

I am writing a PowerShell script that converts a number with a decimal point into an integer.

$val = 1024.24

How to convert this value to integer? (I want it to be 1024)

Vojin Purić · Accepted Answer · 2021-11-24 17:59:42Z

8

Use floor rounding, which rounds to the lower whole number

[Math]::Floor($val)

Edit: if just discarding decimal part is not what you are looking for you can use [Math]::Round($val) which will round the number like normal math rounding or you can use [Math]::Ceiling($val) which will round up (in your case it will round to 1025) and it is probably not what you need but it is good to know that you have these options as well.

answered Nov 24, 2021 at 17:59

Vojin Purić

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4 Comments

Se7en Over a year ago

Thank you! This actually worked. Any ideas for converting a decimal value to the nearest integer? I mean if the value is $val = 1.9 for example, then it is rounded up to $val = 2.0. Does PowerShell have this capability?

Vojin Purić Over a year ago

Yes it is the [Math]::Round($val) I mentioned in the answer

Se7en Over a year ago

YOU ARE THE BEST! yeah [Math]::Round($val) is my solution. (I just saw the edit right now)

mklement0 Over a year ago

@Se7en, note that casting to [int] (or [long], or [decimal], or [bigint], ...) is also an option, but that notably performs half-to-even rounding with .5 values; e.g. [int] 1.5 is 2, but so is [int] 2.5, because the nearest even integer is 2.

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