List of substring matching with file name- python

Question

I want to match the filename by passing a list of substrings to avoid some files in loop if the string matches with the filename. Here's my code:

list_of_files = glob.glob('D:/folder/*.gz') # create the list of file
mylist=['abcd11','abcd12','jklm12','wxyz.12']
for file_name in list_of_files:
   for ind in df.index:
        if df['filename'][ind] in file_name: #filename column contains full file names 
            for i in mylist:
                if i not in file_name:
                    print(file_name)

The thing is, it is also returning filenames which are matching with those list items. following code is working if I pass only one substring in for loop, but I want to match multiple substrings to avoid multiple files.

list_of_files = glob.glob('D:/folder/*.gz') # create the list of file
for file_name in list_of_files:
   for ind in df.index:
        if df['filename'][ind] in file_name: #filename column contains full file names 
            if 'abcd11' not in file_name:
                    print(file_name)

Sorry if this kind of question is already been asked. Thank you!

Bruno Mello · Accepted Answer · 2021-10-31 22:58:02Z

1

Your code should be like this:

list_of_files = glob.glob('D:/folder/*.gz') # create the list of file
mylist=['abcd11','abcd12','jklm12','wxyz.12']
for file_name in list_of_files:
   for ind in df.index:
        if df['filename'][ind] in file_name: #filename column contains full file names 
            is_in_list = False
            for i in mylist:
                if i in file_name:
                    is_in_list = True
            if not is_in_list:
                print(file_name)

The problem with your code is that if the condition:

if i not in file_name:

Is satisfied for one of the elements in mylist, then it will print the name of the file. Whereas, what you want is that it is satisfied for all elements in mylist.

answered Oct 31, 2021 at 22:58

Bruno Mello

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1 Comment

rebel095 Over a year ago

Hello, @Bruno Mello Thanks for your time! I tried the above code but this one also satisfied for one element (first in the loop) in mylist instead for all elements.

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