python round numbers to specific value [duplicate]

Question

I would like to write a specif rounding logic.

number = x

if x < 950:
    # round number to and in steps of 50
elif x < 9000:
    # round number to and in steps of 100
elif x < 100000:
    # round number to and in steps of 250
else:
    # round number to and in steps of 1000

This is my idea how it could work.

What I need for example, if x = 123 then the it should be rounded to 100. if x = 170 it should be rounded to 200, and then for example for x = 8568 it should round to 8600

Something like round(8568/100)*100 or round(170/50)*50 ? — obchardon
– obchardon, Commented Jul 7, 2021 at 9:26
Is x always an integer? Which direction should halfway-cases round (e.g., 825 or 1350)? — Mark Dickinson
– Mark Dickinson, Commented Jul 7, 2021 at 14:27
Why would 170 round to 200 rather than 150? 150 is closer, so it's not clear to me what rule you're using here. — Mark Dickinson
– Mark Dickinson, Commented Jul 7, 2021 at 14:27

Youenn FS · Accepted Answer · 2021-07-07 09:27:09Z

3

Mostlikely not the cleanest way to do it but : (x + step/2)//step*step should work.

Example : print((880+25)//50*50) returns 900.

answered Jul 7, 2021 at 9:27

Youenn FS

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