I have function fun1 that is not IO and can be computationally expensive, so I want to run it for a specified amount of seconds max. I found a function timeout, but it requires this fun1 to be of IO.
timeout :: Int -> IO a -> IO (Maybe a)
How can I circumvent this, or is there a better approach to achieve my goal?
Edit:
I revised first sentence fun1 is NOT IO, it is of type fun1 :: Formula -> Bool.