Check if any arrays in object contain empty values

Question

I have an object called newEntries which has 2 entries so far:

(2) [{…}, {…}]
0: {name: "test", website: "", sector: "", house: ""}
1: {name: "", website: "", sector: "", house: ""}
length: 2
__proto__: Array(0)

As it is visible, currently only one field of one index is filled. I need to return true if all the fields for all elements are filled and false otherwise.

How can I do so in javascript?

It asks about a single string, and this is about an object array with sting values. Quite different. — FZs
– FZs, Commented Mar 10, 2021 at 6:56

dreamcrash · Accepted Answer · 2021-03-10 08:20:07Z

4

Using combo of .every and .some will work for us :-

const array1 = [
{name: "test", website: "fdf", sector: "fdf", house: "fdf"},
{name: "fds", website: "fsd", sector: "fds", house: "fsdf"}]

const array2 = [
{name: "test", website: "", sector: "fdf", house: "fdf"},
{name: "fds", website: "fsd", sector: "fds", house: "fsdf"}]


function checkArray(array){
  return array.every(item => 
    !Object.values(item).some(value => value === "")
  );
}

console.log(checkArray(array1));
console.log(checkArray(array2));

edited Mar 10, 2021 at 8:20

dreamcrash

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answered Mar 10, 2021 at 6:52

Lakshya Thakur

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9 Comments

FZs Over a year ago

Actually, this is very much the same as the two .every's you've had before the edit. Both are correct. (There are no such value, that is an empty string = All values are not equal to an empty string)

Lakshya Thakur Over a year ago

@FZs in the some bit, I think I would skip iterating through rest of the object values as soon as value==="" making this approach better ? Or am I wrong in assuming that ?

FZs Over a year ago

So would it be with the .every. .some is really just an inverted .every...

Lakshya Thakur Over a year ago

So even if a .some condition matches, the subsequent callbacks are still performed nevertheless ?

andi2.2 Over a year ago

Using some indeeed makes the operation way faster (especially if the object gets bigger) I've created a jsbench so everbody can try out himself: jsbench.me/4xkm33t6pw/1

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dreamcrash · Accepted Answer · 2021-03-10 08:19:53Z

4

Using .some:

const filled = !(arr.some(obj => Object.values(obj).some(v => !v)))

edited Mar 10, 2021 at 8:19

dreamcrash

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answered Mar 10, 2021 at 6:51

andi2.2

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Comments

Dan D · Accepted Answer · 2021-03-10 06:53:59Z

1

Just loop thru' all array items and all fields with a flag to check:

var newEntries = [
    {name: "test", website: "", sector: "", house: ""},
    {name: "",     website: "", sector: "", house: ""}
];

for (let i=0; i<newEntries.length; i++){
    let entry     = newEntries[i];
    let allFilled = true;

    for (let field in entry)
        if (entry[field]==""){
            allFilled = false;
            break;
        }

    if (allFilled)
        console.log(entry);
}

edited Mar 10, 2021 at 6:53

answered Mar 10, 2021 at 6:52

Dan D

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2 Comments

andi2.2 Over a year ago

That would work but that's what some/every function were introduced for

Dan D Over a year ago

yeah, that every function is neat

Justin Feakes · Accepted Answer · 2021-03-10 06:55:23Z

1

Loop over the array, and then for each object within it, loop over its properties. If they're empty, return false. Otherwise, it'll get to the end and return true. :)

function checkAll() {
    for (let entry of newEntries) {
        for (let property in entry)
            if(entry[property] === "") return false;
    }
    return true;
}

answered Mar 10, 2021 at 6:55

Justin Feakes

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Comments

Abolfazl Mohajeri · Accepted Answer · 2021-03-10 06:57:32Z

0

hi this is the best way:

var newEntries = [
    {name: "test", website: "", sector: "", house: ""},
    {name: "",     website: "", sector: "", house: ""}
];

let result = true;

for (let i=0; i<newEntries.length; i++){
    let data = newEntries[i];
    let t = Object.values(data).some(val => val);
    if (!t) {
        result = false;
    }
}

console.log(result);

answered Mar 10, 2021 at 6:57

Abolfazl Mohajeri

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1 Comment

FZs Over a year ago

Actually, no, this isn't the best way. It doesn't even work if only the half of an object's properties are empty.

Khwaja Hussam Quasmi · Accepted Answer · 2021-03-10 07:07:06Z

0

Loop through all the items

        var newEntries = [
                {name: "test", website: "", sector: "", house: ""},
                {name: "",     website: "", sector: "", house: ""}
            ];
            newEntries.forEach(myFunction);
            function myFunction(item) {
            if (array === undefined || array.length == 0) {
              return false;
            }
            else{
            return true;
            }
            }

answered Mar 10, 2021 at 7:07

Khwaja Hussam Quasmi

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Comments

Iron Man · Accepted Answer · 2021-03-10 07:16:15Z

0

var arr = [{a:1,b:"",c:"bhj"},{a:1,b:"hgh",c:"bhj"}]
var result = arr.filter(a => a.a != "" && a.b != ""&& a.c != "");
if(result.length===arr.length){
  console.log(true)
}else{
 console.log(false)}

answered Mar 10, 2021 at 7:16

Iron Man

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