Add operators during parsing

Haskell only allows a few precedence levels. So you don't strictly need a dynamic grammar; you could just write out the grammar using precedence-level token classes instead of individual operators, leaving the lexer with the problem of associating a given symbol with a given precedence level.

In effect, that moves the dynamic addition of operators to the lexer. That's a slightly uncomfortable design decision, although in some cases it may not be too difficult to implement. It's uncomfortable design because it requires semantic feedback to the lexer; at a minimum, the lexer needs to consult the symbol table to figure out what type of token it is looking at. In the case of Haskell, at least, this is made more uncomfortable by the fact that fixity declarations are scoped, so in order to track fixity information, the lexer would also need to understand scoping rules.

In practice, most languages which allow program text to define operators and operator precedence work in precisely the same way the Haskell compiler does: expressions are parsed by the grammar into a simple list of items (where parenthesized subexpressions count as a single item), and in a later semantic analysis the list is rearranged into an actual tree taking into account precedence and associativity rules, using a simple version of the shunting yard algorithm. (It's a simple version because it doesn't need to deal with parenthesized subconstructs.)

There are several reasons for this design decision:

1. As mentioned above, for the lexer to figure out what the precedence of a symbol is (or even if the symbol is an operator with precedence) requires a close collaboration between the lexer and the parser, which many would say violates separation of concerns. Worse, it makes it difficult or impossible to use parsing technologies without a small fixed lookahead, such as GLR parsers.

2. Many languages have more precedence levels than Haskell. In some cases, even the number of precedence levels is not defined by the grammar. In Swift, for example, you can declare your own precedence levels, and you define a level not with a number but with a comparison to another previously defined level, leading to a partial order between precedence levels.

   IMHO, that's actually a better design decision than Haskell, in part because it avoids the ambiguity of a precedence level having both left- and right-associative operators, but more importantly because the relative precedence declarations both avoid magic numbers and allow the parser to flag the ambiguous use of operators from different modules. In other words, it does not force a precedence declaration to mechanically apply to any pair of totally unrelated operators; in this sense it makes operator declarations easier to compose.

3. The grammar is much simpler, and arguably easier to understand since most people anyway rely on precedence tables rather than analysing grammar productions to figure out how operators interact with each other. In that sense, having precedence set by the grammar is more a distraction than documentation. See the C++ grammar as a good example of why precedence tables are easier to read than grammars.

   On the other hand, as the C++ grammar also illustrates, a grammar is a lot more general than simple precedence declarations because it can express asymmetric precedences. (The grammar doesn't always express these gracefully, but they can be expressed.) A classic example of an asymmetric precedence is a lambda construct (λ ID expr) which binds very loosely to the right and very tightly to the left: the expected parse of a ∘ λ b b ∘ a does not ever consult the associativity of ∘ because the λ comes between them.

In practice, there is very little cost to building the tree later. The algorithm to build the tree is well-known, simple and cheap.