ipdb commands obscured by variables

Question

When i try to debug this sample script with ipdb:

n = 1
next = 1
print('end')

I can't execute line 3 because python variables obscure pdb commands:

$ ipdb test.py
> /tmp/test.py(1)<module>()
----> 1 n = 1
      2 next = 1
      3 print('end')

ipdb> next
> /tmp/test.py(2)<module>()
      1 n = 1
----> 2 next = 1
      3 print('end')

ipdb> next
> /tmp/test.py(3)<module>()
      1 n = 1
      2 next = 1
----> 3 print('end')

ipdb> next
1
ipdb> n
1
ipdb> !n
1
ipdb> !next
1

How can i proceed further with my code execution when both commands (n/next) aren't recognized anymore? (Let's assume s/step are also obscured by variables).

What i tried so far:

using ipdb3 instead of ipdb - the same problem (maybe because ipdb is link to ipdb3 in my case :))
using pdb - it works! n/next commands move to next line instead of displaying python variables. What's wrong with my ipdb?
!!n alleviates the problem - it runs ipdb version of next. If only I could alias n !!n and then repeatedly use Enter to execute it, the problem would be solved for me. But Enter just displays variable n instead of running alias n (which should resolve into !!n)

I'm using

Manjaro Linux 16.10
Python 3.5.2 :: Anaconda 4.2.0 (64-bit)
ipdb (0.10.1)
ipython (5.1.0)
ipython-genutils (0.1.0)
i don't have ~/.pdbrc file

EDIT

The issue was fixed by by: https://github.com/ipython/ipython/pull/10050

Using pdb3 your example works as expected. Repeated next steps through the program and restarts it while !next shows the value of the variable. Can't reproduce in cpython's pdb. — tdelaney
– tdelaney, Commented Oct 24, 2016 at 17:38
I installed python3-ipdb on my linux machine and it worked there also. next was always treated as a command and !next showed the value of the variable. — tdelaney
– tdelaney, Commented Oct 24, 2016 at 17:44
I added versions of my python/ipdb/ipython to my post. Maybe it makes difference. — Kossak
– Kossak, Commented Oct 24, 2016 at 17:46
!!n should force it to run the command instead of showing the variable. I think !n forces it to treat it as a variable, and n guesses. — Thomas K
– Thomas K, Commented Oct 25, 2016 at 10:28
I have created a pull request to fix the empty line problem you face. github.com/ipython/ipython/pull/10035 — Ziya Tang
– Ziya Tang, Commented Oct 25, 2016 at 22:52

Ziya Tang · Accepted Answer · 2016-12-14 05:18:52Z

2

Update in 12/14/2016:

Finally the iPython team decide to revoke this design.

The solution of your problem is use !! statement to force standard behavior.

> /home/v-zit/test.py(1)<module>()
----> 1 n = 1
      2 next = 11
      3 print('end')

ipdb> n
> /home/v-zit/test.py(2)<module>()
      1 n = 1
----> 2 next = 11
      3 print('end')

ipdb> n
1
ipdb> !!n
> /home/v-zit/test.py(3)<module>()
      1 n = 1
      2 next = 11
----> 3 print('end')

ipdb> next
11
ipdb> !!next
end
--Return--
None
> /home/v-zit/test.py(3)<module>()
      1 n = 1
      2 next = 11
----> 3 print('end')

ipdb>

Reference:

https://github.com/ipython/ipython/pull/9449

https://github.com/ipython/ipython/pull/10050

edited Dec 14, 2016 at 5:18

answered Oct 24, 2016 at 19:15

Ziya Tang

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1 Comment

Kossak Over a year ago

I don't think del n is a workaround - it destroys python variable that the program is using, so it will crash upon reading it.

KingLiu · Accepted Answer · 2022-09-25 08:12:00Z

0

The solution is to use brackets (variable_name).

For example, if you have one vairable named q, you want to check it out, if you directly input q in the prompt, then the ipdb debugging process will break up.

>>> q

Instead, you should input (q) to ckeck this vairable:

>>> (q)

answered Sep 25, 2022 at 8:12

KingLiu

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