Swift: Extending functionality of print() function

Question

Is it possible to extend the functionality of a Swift function? I would like appnd a single character onto every print() function in my program without having to create a brand new function and renaming every instance of print(). Is it possible to create an extension that will append an '*' onto every print instance?

The purpose of this is to create a way of flushing out all of the extra information that XCODE adds into the debugger. I am using print statements to check on the progress and success of different parts of my code, but XCODE fills in thousands of lines of excess info in seconds that quickly cover up my specific statements.

What I want to do:

print("Hello world!")
//Psuedo code:
Extension print(text: String) {
    let newText = "*\(text)"
    return newText
}

Output: *Hello World!

I will then filter the Xcode debugging output for asterisks. I have been doing this manually

If this is in Xcode, have you tried just switching to "Target Output" in the debug window rather than "All Output?" — Rob Napier
– Rob Napier, Commented Aug 18, 2016 at 20:53

Chackle · Accepted Answer · 2020-02-28 19:23:37Z

31

You can overshadow the print method from the standard library:

public func print(items: Any..., separator: String = " ", terminator: String = "\n") {
    let output = items.map { "*\($0)" }.joined(separator: separator)
    Swift.print(output, terminator: terminator)
}

Since the original function is in the standard library, its fully qualified name is Swift.print

edited Feb 28, 2020 at 19:23

Chackle

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answered Aug 18, 2016 at 20:43

Code Different

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7 Comments

Alexander Over a year ago

Is this "overriding"? I think it's just "shadowing"

Alec O Over a year ago

Where can I place this function so that it is available in all files? And is there a way to use this function without having to add items: in such as print(items: "Hello")

Code Different Over a year ago

Make a new .swift file and place it there. if you are using Swift 2, you don't have to specify the item: label. The code won't work with Swift 3 anyway.

RemyNL Over a year ago

Is there a swift3 solution to this? Because it is xcode8 that is adding all the unwanted extra garbage to the console.... (which seems to be a 'known issue' and is no longer the case with xcode8.1 beta....) My point being, xcode8 and swift3 are like big buddies... This code not working in Swift3 is kinda missing the point. I would love to have a temporary print replacement that works in swift3.... Or maybe I should just go for xcode8.1 beta.... Little unexperienced in the beta-channel, does it replace your stable version of xcode or can the exist next to eachother?

Programus Over a year ago

I just tried this in swift3/xcode 8.3. You can just add a _ before items. public func print(_ items: Any..., separator: String = " ", terminator: String = "\n") {...}

|

PiterPan · Accepted Answer · 2020-01-03 10:13:13Z

If we want to cover all cases with custom print we should create new file for example: CustomPrint.swift and then paste this two methods:

SWIFT 5.1

First (according to ThomasHaz answer)

public func print(_ items: String..., filename: String = #file, function : String = #function, line: Int = #line, separator: String = " ", terminator: String = "\n") {
    #if DEBUG
        let pretty = "\(URL(fileURLWithPath: filename).lastPathComponent) [#\(line)] \(function)\n\t-> "
        let output = items.map { "\($0)" }.joined(separator: separator)
        Swift.print(pretty+output, terminator: terminator)
    #else
        Swift.print("RELEASE MODE")
    #endif
}

and second because the first one does't cover dictionary and array printing

public func print(_ items: Any..., separator: String = " ", terminator: String = "\n") {
    #if DEBUG
        let output = items.map { "\($0)" }.joined(separator: separator)
        Swift.print(output, terminator: terminator)
    #else
        Swift.print("RELEASE MODE")
    #endif
}

Enjoy :)

Nehrulal Hingwe · Accepted Answer · 2017-11-10 12:48:28Z

20

This code working for me in swift 3

import Foundation

public func print(_ items: Any..., separator: String = " ", terminator: String = "\n") {
    let output = items.map { "\($0)" }.joined(separator: separator)
    Swift.print(output, terminator: terminator)
}

class YourViewController: UIViewController {
}

answered Nov 10, 2017 at 12:48

Nehrulal Hingwe

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