python 2d array list index out of range

Question

j=0
i=0
text=[[0 for x in range(5)]for y in range(2)]
while (i<5):
    for link in soup.findAll('td'):
        if j<2:
            text[i][j]=link.string
            j+=1
i+=1

The problem is I get the error message list index out of range but I already set the if condition so if j exceed 3 will nth happen. So what is the problem?

you get your i and j indices mixed up.

Julien
– Julien

2016-07-29 07:56:18 +00:00
Commented Jul 29, 2016 at 7:56 — Julien
– Julien, Commented Jul 29, 2016 at 7:56

EngineerCamp · Accepted Answer · 2016-07-29 07:57:37Z

1

[[0 for x in range(5)] for y in range(2)]

creates the array [[0, 0, 0, 0, 0], [0, 0, 0, 0, 0]]

Your code is built for an array which looks like: [[0, 0], [0, 0],[0, 0],[0, 0],[0, 0]].

So either i and j are around the wrong way or your:

[[0 for x in range(5)] for y in range(2)]

isn't giving you what you expect.

answered Jul 29, 2016 at 7:57

EngineerCamp

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Comments

Xyrus · Accepted Answer · 2016-07-29 08:07:03Z

1

text=[[0 for x in range(5)]for y in range(2)]

is equal to

[[0, 0, 0, 0, 0], [0, 0, 0, 0, 0]]

So inside your list, you have 2 lists with 5 elements each one.

Then look at this line:

text[i][j]=link.string

i - is number of elements in variable text (you have 2)

j - is number of elements in each list (you have 5 elements)

It looks like you have mixed i and j.

answered Jul 29, 2016 at 8:07

Xyrus

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