There are two images placed one below the other, what i want to do is when you hover a mouse over the top image only the portion of the image below should be visible not the entire image to be replaced.Is this possible using jquery ?.
I am stuck on where to start. I tried changing the div background on hover but i couldn't get anywhere near what i need.Thanks.
html
<div style="background-image: url("image1.jpg")></div>
<div style="background-image: url("image2.jpg")></div>
Try this?
$(document).ready(function() {
var $hover = $("#hover");
var $foreground = $("#foreground");
$hover.hide();
$foreground.mousemove(function(event) {
var top = event.pageY - $hover.height() / 2;
var left = event.pageX - $hover.width() / 2;
$hover.css("top", top);
$hover.css("left", left);
});
$foreground.mouseover(function() {
$hover.show();
});
$foreground.mouseleave(function() {
$hover.hide();
});
});
http://jsfiddle.net/WV8jX/685/
EDIT: Updated to hide before mouse entering http://jsfiddle.net/WV8jX/686/
EDIT: It doesn't really solve your problem tho if you need the background to be shown as according to your description.
Since you have tagged jQuery, use the jQuery .hover().
Example:
$("selector").hover(
function() {
show your hidden image functionality here
}
);
I think there is no need of using Javascript/Jquery. CSS can do the job as below
HTML
<div class="bgdemo"></div>
CSS
.bgdemo{
background-image: url("image1.jpg");
}
.bgdemo:hover{
background-image: url("image2.jpg");
}
and there is a typo in your HTML, style tag is not ending properly.
edit
Check this jsfiddle, Position the background according to your requirement.
edit
Here I found good article seems bit complicated but worth reading..
