Accessing variable inside a static function class

Question

I have a login.php and authenticate.php

I want to access a variable inside the authenticate.php inside a class. I want to get the error message from authenticate class to my login.php

This is my class inside Authenticate.php

Class Authenticate {

    public $invalidUserErrMsg = "sdfs";

    static public function LDAPAuthenticate() {
                 //connection stuff
            } else {
                $msg = "Invalid username / password";
                $this->invalidUserErrMsg = $msg;

            }
    }

    static public function invalidUserErr() {
        echo $hits->invalidUserErrMsg;
        return $this->invalidUserErrMsg;
    }

}

This is how I'm printing inside login.php

<?php 
    $error = new Authenticate();
    $error->invalidUserErr(); 
?>

You're returning the value from invalidUserErr() so just assign that when you call it in your login — Mark Baker
– Mark Baker, Commented Jan 12, 2016 at 9:59
you get an error because there is not if() within the LDAPAuthenticate() — Frank W.
– Frank W., Commented Jan 12, 2016 at 10:14
@Lars There's a condition inside that function, and the message si returning within the class, I just want to position the error message properly cause its showing on the top of the page. — suisied
– suisied, Commented Jan 12, 2016 at 10:15

Frank W. · Accepted Answer · 2016-05-12 13:34:01Z

3

Class Authenticate {

    public $invalidUserErrMsg = "sdfs";

    public function LDAPAuthenticate() {
        if($hello) {
             echo 'hello';
        } else {
            $msg = "Invalid username / password";
            $this->invalidUserErrMsg = $msg;

        }
}

   public function invalidUserErr() {
        return $this->invalidUserErrMsg;
    }

}

<?php 
    $error = new Authenticate();
    echo $error->invalidUserErr(); 
?>

Don't echo the variable within the class but echo the method on login.php. There is no need to make it a static function if you are going to instantiate the object anyway.

Check out this page on the static keyword

edited May 12, 2016 at 13:34

answered Jan 12, 2016 at 10:00

Frank W.

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8 Comments

suisied Over a year ago

Fatal error: Uncaught Error: Call to undefined method Authenticate::invalidUserErr()

Frank W. Over a year ago

That is because you declared the function as static

Frank W. Over a year ago

Just tested the code 'as is' in my answer and it works

suisied Over a year ago

didn't see the echo part! thnaks!

Frank W. Over a year ago

No worries, Good luck ;)

|

ScaisEdge · Accepted Answer · 2016-01-12 10:01:05Z

0

For accessing static function you need

<?php 
  $error = new Authenticate::invalidUserErr();

?>

answered Jan 12, 2016 at 10:01

ScaisEdge

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