Python Code for Triangles

Question

I have this task to do :Write a procedure called triangle that takes in a number and then prints out a triangle of that height.Like this:

      *
     ***
    *****
   *******

The only solution I found was this code :

def triangle(size):
    spaces=""
    stars=""
    line=""
    for i in range(0,size):
        for j in range(0,(size-1-i)+11-(size-1-i)-i): 
            line=line+" "

        for k in range(0,2*i+1):
            line=line+"*"

        print(line)
        line=""

    triangle(2)
    triangle(3)
    triangle(4)

I just want to know does anyone have a simpler way of doing this or a way to simplify this code and making it more readable?

What's wrong with this? This code pretty much simple and readable to me...and self explanatory as well. — vish4071
– vish4071, Commented Dec 31, 2015 at 7:29
i understand the Structure , But I don't understand how the person worked out the calculations to form the triangle e.g line 6 — 123abc
– 123abc, Commented Dec 31, 2015 at 9:36
Don't try to understand the calculus of line 6, as it is bugged. Try calling triangle(15) for example. — DainDwarf
– DainDwarf, Commented Dec 31, 2015 at 9:44

DainDwarf · Accepted Answer · 2015-12-31 07:47:41Z

9

Here is a one-liner that will probably prove your teacher you copied from internet:

Edited following OP edit:

def triangle(n) : print('\n'.join(map(lambda i:('{:^'+str(2*n)+'}').format('*'*(2*i+1)), range(n))))

edited Dec 31, 2015 at 7:47

answered Dec 31, 2015 at 7:13

DainDwarf

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9 Comments

DainDwarf Over a year ago

And here is my funnier one-liner : def triangle(n) : print('\n'.join(map(lambda i:'*'*(2*i+1), range(n))))

DainDwarf Over a year ago

And here is a centered triangle: def triangle(n) : print('\n'.join(map(lambda i:('{:^'+str(2*n)+'}').format('*'*(2*i+1)), range(n))))

TigerhawkT3 Over a year ago

Can you replace the answer as it currently stands with your last comment here? As it is, it doesn't actually answer the question.

DainDwarf Over a year ago

OP reformatted the question. I've edited my answer to give the correct answer. :)

123abc Over a year ago

Idiot me sorry. ;) and Thanks p.s. Can you explain line 6 for me please I don't know how the person done the calculations.

|

TigerhawkT3 · Accepted Answer · 2015-12-31 07:41:22Z

2

As you're using Python 3, you have some nice options with the print() function:

def triangle(size):
    print(*(('{:^'+str(2*size+1)+'}').format('*'*row) for row in range(1, 2*size+1, 2)), sep='\n')

This creates a formatted string that centers the proper number of stars for each row, and then sends each row as an argument to print(), with a newline as a separator.

>>> triangle(4)
    *
   ***
  *****
 *******
>>> triangle(5)
     *
    ***
   *****
  *******
 *********

answered Dec 31, 2015 at 7:41

TigerhawkT3

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Comments

Rahul · Accepted Answer · 2019-10-04 18:34:30Z

2

def triangle(line):
    for numberofsymbol in range(line):
        for j in range(line-numberofsymbol): print(" ", end='')
        for j in range(numberofsymbol): print("* ", end='')
        print("")

triangle(10)


OUPUT:
         * 
        * * 
       * * * 
      * * * * 
     * * * * * 
    * * * * * * 
   * * * * * * * 
  * * * * * * * * 
 * * * * * * * * *

edited Oct 4, 2019 at 18:34

answered Oct 4, 2019 at 18:29

Rahul

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