Creating variable array for keycode

Question

I am trying to create a single variable that contains all of the function key codes. If I remove the brackets and use a single keycode everything works.

$('input').keyup(function (e) {

    var functionKeysPressed = e.which == [114, 115, 116, etc];

    if (!functionKeysPressed) {

    }

});

AmmarCSE · Accepted Answer · 2015-07-07 13:03:43Z

4

Use indexOf()

$('input').keyup(function (e) {

    var functionKeysPressed = [114, 115, 116, etc].indexOf(e.which) > -1;

    if (!functionKeysPressed) {

    }

});

answered Jul 7, 2015 at 13:03

AmmarCSE

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Comments

suvroc · Accepted Answer · 2015-07-07 13:03:50Z

0

To check if element exist in array you should use indexOf

function contains(e) {    
    return [114, 115, 116, etc].indexOf(e.which) != -1;
}

answered Jul 7, 2015 at 13:03

suvroc

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Comments

Praveen Kumar Purushothaman · Accepted Answer · 2015-07-07 13:04:06Z

0

Use indexOf to see if that is existing:

[114, 115, 116, etc].indexOf(e.which) != -1

So your code becomes:

$('input').keyup(function (e) {
    var functionKeysPressed = [114, 115, 116, etc].indexOf(e.which) != -1;
    if (!functionKeysPressed) {

    }
});

answered Jul 7, 2015 at 13:04

Praveen Kumar Purushothaman

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