How to check if a file exists, without using .path

Question

Is there any way that you can check if a file exists in the same folder as the program without using:

os.path.isfile or os.path.exists

Why would you not use os.path?

JonB
– JonB

2015-02-23 17:28:21 +00:00
Commented Feb 23, 2015 at 17:28 — JonB
– JonB, Commented Feb 23, 2015 at 17:28

MChan · Accepted Answer · 2015-02-23 18:36:19Z

1

You can still use os.path without 'changing paths all the time', as you outlined in your comment.

import os

def is_file_in_app_path(filename):
    app_path = os.path.dirname(os.path.realpath(__file__))
    file_path = os.path.join(app_path, filename)
    return os.path.exists(file_path)

Fixed as per @tdelaney's comment.

edited Feb 23, 2015 at 18:36

answered Feb 23, 2015 at 18:26

MChan

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1 Comment

tdelaney Over a year ago

os.path.join is a platform independent version of '/'.join(...)

Maddy · Accepted Answer · 2015-02-23 17:23:54Z

0

import os

def openFile(filename):
    try:
        fd = os.open(filename, os.O_CREAT | os.O_EXCL | os.O_WRONLY)
    except:
        print "Nothing here"
        return None
    fobj = os.fdopen(fd, "w")
    return fobj

answered Feb 23, 2015 at 17:23

Maddy

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