Is there an until statement or loop in python? This does not work:
x = 10
list = []
until x = 0:
list.append(raw_input('Enter a word: '))
x-=1
-
See also: Is there a “do … until” in Python? and Repeat-Until loop in python or equivalentJohn1024– John10242015-02-10 04:03:19 +00:00Commented Feb 10, 2015 at 4:03
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4 Answers
The equivalent is a while x1 != x2 loop.
Thus, your code becomes:
x = 10
lst = [] #Note: do not use list as a variable name, it shadows the built-in
while x != 0:
lst.append(raw_input('Enter a word: '))
x-=1
Comments
while x != 0:
#do stuff
This will run until x == 0
Comments
You don't really need to count how many times you're looping unless you're doing something with that variable. Instead, you can use a for loop that will fire up to 10 times instead:
li = []
for x in range(10):
li.append(raw_input('Enter a word: '))
As an aside, don't use list as a variable name, as that masks the actual list method.
Comments
Python emulates until loops with the iter(iterable, sentinel) idiom:
x = 10
list = []
for x in iter(lambda: x-1, 0):
list.append(raw_input('Enter a word: '))
- I was forced to construct a trivial lambda for demonstration purposes; here a simple
range()would suffice, as as @Makoto suggested.
