Pugixml C++ parsing XML

Question

I am a newbie in pugixml. Consider I have XML given here. I want to get value of Name and Roll of Every Student. The code below only find the tag but not the value.

#include <iostream>
#include "pugixml.hpp"

int main()
{
    std::string xml_mesg = "<data> \
    <student>\
       <Name>student 1</Name>\
       <Roll>111</Roll>\
    </student>\
    <student>\
        <Name>student 2</Name>\
        <Roll>222</Roll>\
    </student>\
    <student>\
        <Name>student 3</Name>\
        <Roll>333</Roll>\
    </student>\
</data>";
    pugi::xml_document doc;
    doc.load_string(xml_mesg.c_str());
    pugi::xml_node data = doc.child("data");
    for(pugi::xml_node_iterator it=data.begin(); it!=data.end(); ++it)
    {
        for(pugi::xml_node_iterator itt=it->begin(); itt!=it->end(); ++itt)
            std::cout << itt->name() << " " << std::endl;
    }
    return 0;
}

I want the output of Name and Roll for each student. How can I modify above code? Also, if one can refer here(press Test), I can directly write xpath which is supported by pugixml. If so, how can I get the values I seek using Xpath in Pugixml.

Cornstalks · Accepted Answer · 2015-01-08 16:05:10Z

1

Here's how you can do it with just Xpath:

pugi::xpath_query student_query("/data/student");

pugi::xpath_query name_query("Name/text()");
pugi::xpath_query roll_query("Roll/text()");

pugi::xpath_node_set xpath_students = doc.select_nodes(student_query);
for (pugi::xpath_node xpath_student : xpath_students)
{
    // Since Xpath results can be nodes or attributes, you must explicitly get
    // the node out with .node()
    pugi::xml_node student = xpath_student.node();

    pugi::xml_node name = student.select_node(name_query).node();
    pugi::xml_node roll = student.select_node(roll_query).node();

    std::cout << "Student name: " << name.value() << std::endl;
    std::cout << "        roll: " << roll.value() << std::endl;
}

answered Jan 8, 2015 at 16:05

Cornstalks

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2 Comments

Mahadeva Over a year ago

Thank you I will try this but how can I change my code so that it gets the value I desire?

Cornstalks Over a year ago

Just put my code right after the line doc.load_string(xml_mesg.c_str());

Nelly Sugu · Accepted Answer · 2015-01-08 17:07:19Z

1

I think that the reason why you are getting the "tags/nodes" instead of their values is because you are using the name() function instead of value(). Try replacing your itt->name() with itt->value() instead. I found some good documentation about accessing document data here

answered Jan 8, 2015 at 17:07

Nelly Sugu

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1 Comment

Nelly Sugu Over a year ago

Some more good documentation here

Community · Accepted Answer · 2017-05-23 10:27:23Z

Thanks @Cornstalks for the insight of using xpath in pugixml. I used child_value given here. The code of mine was thus:

    for(pugi::xml_node_iterator it=data.begin(); it!=data.end(); ++it)
    {
        for(pugi::xml_node_iterator itt=it->begin(); itt!=it->end(); ++itt)
            std::cout << itt->name() << " " << itt->child_value() << " " << std::endl;
    }

I could also use xpath as @Cornstalks suggested thus making my code as:

pugi::xml_document doc;
doc.load_string(xml_mesg.c_str());
pugi::xpath_query student_query("/data/student");

pugi::xpath_query name_query("Name/text()");
pugi::xpath_query roll_query("Roll/text()");

pugi::xpath_node_set xpath_students = doc.select_nodes(student_query);
for (pugi::xpath_node xpath_student : xpath_students)
{
    // Since Xpath results can be nodes or attributes, you must explicitly get
    // the node out with .node()
    pugi::xml_node student = xpath_student.node();

    pugi::xml_node name = student.select_node(name_query).node();
    pugi::xml_node roll = student.select_node(roll_query).node();

    std::cout << "Student name: " << name.value() << std::endl;
    std::cout << "        roll: " << roll.value() << std::endl;
}

Akshay Mahajan · Accepted Answer · 2016-09-26 08:24:21Z

0

In your inner loop change the following line to get the values like : student1 and 111 and so on...

std::cout << itt.text().get() << " " << std::endl;

answered Sep 26, 2016 at 8:24

Akshay Mahajan

14 bronze badges

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