ipython post-mortem debugging: scope of outer function

Question

Consider the following code:

def inner(a):
    if a == 75:
        raise RuntimeError()
    return a**2

def outer():
    results = []
    for a in range(100):
        results.append(inner(a))
    return results

outer()

In IPython, after the exception was raised, the %debug line magic opens the python debugger at the scope of inner():

In [4]: %debug
> <ipython-input-3-eff43b15b2ef>(3)inner()
      2     if a == 75:
----> 3         raise RuntimeError()
      4     return a**2

ipdb> a
a = 75
ipdb> results
*** NameError: name 'results' is not defined

How can you tell (i)pdb to enter the scope of outer() in order to save the results generated so far?

Seb D. · Accepted Answer · 2015-01-08 08:50:23Z

7

I don't think you can directly do it. However, once inside the debugger, you can easily type u (for up) to move the current frame one level up and be inside the outer function. See here for more informations on the commands.

answered Jan 8, 2015 at 8:50

Seb D.

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