Get file name before the extension

Question

I have some files in the same directory (in UNIX filesystem) that looks like:

a.txt.name
b.xml.name
c.properties.name

a.txt.name2
b.xml.name2
c.properties.name2

How do I get the string before the name or name2 part using some shell command?

ie. the a.txt, b.xml, c.properties part?

Thomas · Accepted Answer · 2010-05-04 16:40:48Z

9

$ basename a.txt.name .name
a.txt

answered May 4, 2010 at 16:40

Thomas

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Comments

Dennis Williamson · Accepted Answer · 2010-05-04 17:34:42Z

4

$ file="a.txt.name"
$ file="${file%.*}"
$ echo "$file"
a.txt

answered May 4, 2010 at 17:34

Dennis Williamson

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Comments

Ram · Accepted Answer · 2014-11-01 03:07:45Z

2

If naming convention is always foo.bar.other , then this is simple enough:

ls * | cut -d. -f1,2

edited Nov 1, 2014 at 3:07

Ram

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answered May 4, 2010 at 17:44

DaveG

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Comments

Steve Robillard · Accepted Answer · 2013-02-27 15:35:17Z

1

Take a look at the bash string manipulation functions. This page should get you most of the way there:

http://tldp.org/LDP/abs/html/string-manipulation.html

edited Feb 27, 2013 at 15:35

user142162

answered May 4, 2010 at 16:42

Steve Robillard

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