C Programming — get multiple words in string

Your variable char **global; is a disaster zone. It is a null pointer. It must be made to point to some valid data before it can be used. It is a double pointer, in fact, so you have to make space available like this:

char array[1000];
char *pointer = array;
char **global = &pointer;

Now you could safely use global[0].

Inside the function, you pass &global to scanf(); that is a char ***. Being a 'Three-Star Programmer' is not a good thing, especially when you do it by accident and not by design.

You include the header <string.h> but don't use any of its functions. You do use functions from <stdio.h> and you don't include that. Technically, you invoke undefined behaviour by using the variadic functions printf() and scanf() without a function prototype in scope. The compiler is entitled to be told about functions that take a variable number of arguments (that's what 'variadic' means), and is entitled to miscompile code where it is not told that the function is variadic.

Assuming you really do need a global variable at all (they're generally not a good idea and you should avoid using them as much as possible), then you could reasonably write:

#include <stdio.h>

char global[1000];

int main(void)
{
    printf("Please Enter Text: ");
    if (scanf("%s", global) == 1)
        printf("%s\n", global);
    return 0;
}

This is at least sound code, but it still has your original problem that it reads only one word, not a whole line.

Forget that gets() exists. It was one of the buggy functions used in the first Internet Worm of 1988 (Google for 'morris internet worm'). It is irredeemable; it cannot be used safely in a hostile environment, and all programming has to be done assuming a hostile environment.

To read a line, use fgets().

#include <stdio.h>
#include <string.h>

char global[1000];

int main(void)
{
    printf("Please Enter Text: ");
    if (fgets(global, sizeof(global), stdin) != NULL)
    {
        size_t len = strlen(global);
        if (len != 0 && global[len-1] == '\n')
            global[--len] = '\0';
        printf("%s\n", global);
    }
    return 0;
}

This gets a line of data into global.

You can legitimately ask how len could ever be zero (I asked it of myself, and I replaced assert(len != 0) because of the answer). One answer would be 'standard input was redirected from a binary file and the first byte was a null (zero) byte'. Then fgets() would read data including the null byte up to the first newline, but the strlen() would stop at the null byte, reporting 0 as the length.

The code removes the newline from the string, and determines its length at the same time — you normally need that length. It then prints it. Notice that the code checks that fgets() succeeded. I/O (especially input) has a habit of breaking when you aren't looking. A lot of the time, it will work fine, but to make your program robust, you have to be paranoid about input operations failing (and, later, memory allocations failing).

Are you looking for something like this:-

 scanf("%[^\t\n]",&global);

Also in your printf & is not required. It should be like:

printf("%s", global);