Pattern matching with grep [duplicate]

Question

I have a full path of a file say hai/hello/home/something/file.txt .How can I get file.txt as output eliminating full path?

How to do that with grep?

pkm · Accepted Answer · 2013-10-03 07:03:15Z

2

#!/usr/bin/perl
use File::Spec;
use File::Basename;
$n="hai/hello/home/something/file.txt";
my $m = basename $n;
print "$m";

answered Oct 3, 2013 at 7:03

pkm

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Comments

Nikhil · Accepted Answer · 2013-10-03 06:55:40Z

1

You don't strictly need grep for this, but if you insist, this should work:

grep -o -e "\w*\.\w*$"

Optionally, consider the command basename:

basename hai/hello/home/something/file.txt

answered Oct 3, 2013 at 6:55

Nikhil

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mvp · Accepted Answer · 2013-10-03 06:55:46Z

1

You can do it using sed:

$ echo hai/hello/home/something/file.txt | sed "s|.*/||g"
file.txt

$ basename hai/hello/home/something/file.txt
file.txt

answered Oct 3, 2013 at 6:55

mvp

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