python function to set accuracy of float

Question

I would like to make a function:

def accuracy(number, index):

For example

accuracy(2.5e-10, -5) would return 0.
accuracy(49, 2) would return 0.
accuracy(50, 2) would return 100.

So basically it would round to the closest 10 power of the index index How would you do that?

... by using round()? What is the problem with your code, do you get an error or incorrect results? — user395760
– user395760, Commented Aug 13, 2013 at 21:20

cordoro · Accepted Answer · 2013-08-13 22:07:32Z

3

def accuracy(n, i):
    return round(float(n) / 10**i) * 10**i

cordoro

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answered Aug 13, 2013 at 21:21

Paul Evans

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1 Comment

round(float(n), -i) is simpler.