Shell Script: grep and replace

Question

I have a file "test.htm" with the follwoing content

<html>

<head></head>

<body>site-is-down</body>

</html>

I am trying to make it "site-is-up" if it has text "site-is-down". When I execute the script its showing correct output ,but its not replacing anything in the file

 #!/bin/ksh
if grep "site-is-down" test.htm; then
 sed -e "s/down/up/g" test.htm
else
 echo "Site is already up"
fi

user21926 · Accepted Answer · 2013-07-29 16:36:25Z

1

Change this line:

sed -e "s/down/up/g" test.htm

To this:

sed -i -e "s/down/up/g" test.htm

The -i flag means to edit the file "in-place" rather than to write the replacements to standard output.

answered Jul 29, 2013 at 16:36

user21926

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Comments

Nitish Kumar Pal · Accepted Answer · 2019-10-23 07:09:07Z

0

To replace every occurrence of a certain word / string in a ton of files spanning multiple directories, and this is the quickest way I've found to do it. It uses grep to search for a certain word and if it find its it runs sed to replace the strings you want.

grep -rl matchstring somedir/ | xargs sed -i 's/string1/string2/g'

answered Oct 23, 2019 at 7:09

Nitish Kumar Pal

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