Bash - extract file name and extension from a string

Question

Here is grep command:

grep "%SWFPATH%/plugins/" filename

And its output:

set(hotspot[hs_bg_%2].url,%SWFPATH%/plugins/textfield.swf);
set(hotspot[hs_%2].url,%SWFPATH%/plugins/textfield.swf);
url="%SWFPATH%/plugins/textfield.swf"
url="%SWFPATH%/plugins/scrollarea.swf"
alturl="%SWFPATH%/plugins/scrollarea.js"
url="%SWFPATH%/plugins/textfield.swf"

I'd like to generate a file containing the names of the all files in the 'plugins/' directory, that are mentioned in a certain file.

Basically I need to extract the file name and the extension from every line. I can manage to delete any duplicates but I can't figure out how to extract the information that I need.

This would be the content of the file that I would like to get:

textfield.swf
scrollarea.swf
strollarea.js

Thanks!!!

PS: The thread "Extract filename and extension in bash (14 answers)" explains how to get filename and extension from a 'variable'. What I'm trying to achieve is extracting these from a 'file', which is completely different'

possible duplicate of Extract filename and extension in bash — Marc B
– Marc B, Commented Jun 6, 2013 at 16:57

blue · Accepted Answer · 2013-06-06 17:20:09Z

2

Using awk:

grep "%SWFPATH%/plugins/" filename | \
awk '{ match($0, /plugins\/([^\/[:space:]]+)\.([[:alnum:]]+)/,submatch);
     print "filename:"submatch[1];
     print "extension:"submatch[2];
    }'

Some explanation:

the match function takes every line processed by awk (indicated by $0) and looks for matches to that regex. Submatches (the parts of the string that match the parts of the regex between parentheses) are saved in the array submatch. print is as straightforward as it looks, it just prints stuff.

edited Jun 6, 2013 at 17:20

answered Jun 6, 2013 at 17:04

blue

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1 Comment

RafaelGP Over a year ago

Sorry, I get the following error "awk: line 1: syntax error at or near,"

iruvar · Accepted Answer · 2013-06-06 20:49:53Z

1

For this specific problem

awk '/\/plugins\// {sub(/.*\//, ""); sub(/(\);|")?$/, "");
   arr[$0] = $0} END {for (i in arr) print arr[i]}' filename

edited Jun 6, 2013 at 20:49

answered Jun 6, 2013 at 17:05

iruvar

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4 Comments

blue Over a year ago

the second sub does not work well with the first two strings

iruvar Over a year ago

@blue, added in a different solution

RafaelGP Over a year ago

Thanks! Worked like a charm. I didn't have any preblems with the second 'sub'

iruvar Over a year ago

@RafaelGP, good to know! Blue pointed out an issue with the second sub in my original answer that I was able to subsequently fix, so you no longer see the issue in the latest answer. Cheers.

suspectus · Accepted Answer · 2013-06-06 17:08:04Z

1

Use awk to simply extract the filename and then sed to clean up the trailing )"; characters.

 awk -F/ '{print $NF}' a  | sed -e 's/);//' -e 's/"$//'

answered Jun 6, 2013 at 17:08

suspectus

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