Generating a random number using a timer in capl

Question

I was trying to generate a random number in CAPL program (similar to C language) using timers. Say I have a timer X and I start it

/****Timer start****/
on start
{ 
  settimer (x,20000);   // setting the timer for 20 secs
}

Now I need a random number only between 300ms to 20 secs with a resolution of 500ms. CAPL has a inbuilt function called random() to do this.

I did like

int random(int x);

Now how can I make sure that I get a random value only with resolution of 500ms?

Any suggestions?

Dmitry Grigoryev · Accepted Answer · 2015-06-19 08:27:46Z

1

How about

y = random(40);
TestWaitForTimeout(300+y*500);

y gets a random value between 0 and 39, corresponding to 0-19.5 seconds with 500 ms resolution. Then you add 300ms to the total timeout. The resulting timeout will be between 300ms and 20s with a resolution of 500ms.

answered Jun 19, 2015 at 8:27

Dmitry Grigoryev

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Comments

Ander Biguri · Accepted Answer · 2013-05-14 14:23:17Z

0

I was able to generate random numbers by writing a test function as below. The random function generates a random number between 0 to n-1. As far as resolution is concerned the library function random() doesn't allow to vary the resolution.

testfunction Random_No ()

{

dword y;

y = random(20000);


TestWaitForTimeout(y);

}

edited May 14, 2013 at 14:23

Ander Biguri

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answered May 14, 2013 at 13:49

Developer

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