Passing variables to JQuery animate

Question

$(document).ready(function(){
for(var i=1;i<5;i++){
    var pos = -411*i;
    var pospx = "{'background-position-x':'"+ pos.toString() + "px'}";
    $("#newsPix").delay(2000).animate(pospx, 1000);
    }
});

I'm a jquery beginner, and I'm trying to use animated sprites to make something similar to a slideshow. I've been trying to make this code work for hours but I'm not sure where the probelm is! I've checked the HTML and CSS and they seem fine. I think the problem lies in either passing a value to the animate method OR in string adding for the pospx variable. any ideas?

Can you make a Fiddle that reflects your problem?

Mooseman
– Mooseman

2013-02-04 18:32:44 +00:00
Commented Feb 4, 2013 at 18:32 — Mooseman
– Mooseman, Commented Feb 4, 2013 at 18:32

adeneo · Accepted Answer · 2013-02-04 18:33:21Z

8

You're passing a string, an object would be more appropriate as that is what animate() accepts :

$(document).ready(function(){
    for(var i=1; i<5; i++){
        var pos   = -411*i,
            pospx = {'background-position-x' : pos};

        $("#newsPix").delay(2000).animate(pospx, 1000);
    }
});

And background-position-x is not supported in all browsers.

answered Feb 4, 2013 at 18:33

adeneo

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2 Comments

adeneo Over a year ago

@EslamA.Hefnawy - no problem, you'll get more priveliges as you participate and post a few more questions / answers, and then it's a lot more fun.

Rashed Shaon Over a year ago

in my case I follow the given code but not work if I set the value manually then it's working fine ` for(var i = from; i<4; i++){ var p = $("#tab"+i).css('right'); if(p){ p = 300;//parseInt(p.replace('px','')); } //alert(position); position = {right: p}; $("#tab"+i).delay(2000).animate(position).animate(pospx, 1000); }`

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