C++ struct error - error C2061: syntax error : identifier

Question

This is my code:

struct opts
{
   int a;
   int b;
};
class myclass
{
  private:
           opts options;
 public:
       void afunction();
}

//myclass.cpp
void myclass::afunction()
{
     if options.a==1
           //do something
}

When I compile it I am getting the follwoing error.

error C2061: syntax error : identifier options

What is wrong with it?

You're missing a ; after class myclass {...}.

user1233508
– user1233508

2012-11-20 15:09:25 +00:00
Commented Nov 20, 2012 at 15:09 — user1233508
– user1233508, Commented Nov 20, 2012 at 15:09

Luchian Grigore · Accepted Answer · 2012-11-20 15:08:02Z

4

 if options.a==1

is wrong. The condition has to be surrounded by parenthesis.

 if (options.a==1)

answered Nov 20, 2012 at 15:08

Luchian Grigore

260k68 gold badges465 silver badges634 bronze badges

Sign up to request clarification or add additional context in comments.

1 Comment

unwind Over a year ago

This is of course another problem with the code, but it's weird that it's accepted, since the issue pointed out by DCoder in a comment seems to be the root cause of the error.

Collectives™ on Stack Overflow

C++ struct error - error C2061: syntax error : identifier

1 Answer 1

1 Comment

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

1 Comment

Your Answer

Sign up or log in

Post as a guest

Related