How to convert the char array to unsigned int?

Question

I have the following code:

volatile unsigned int * address;
char * array="0x10000008";

Please tell me, what is a correct way of writing the "array" value to "address" variable?

Paul R · Accepted Answer · 2012-10-23 07:29:35Z

6

You could use sscanf:

#include <stdio.h>

sscanf(array, "%p", &address);

or strtoull:

#include <stdlib.h>

address = (unsigned int *)strtoull(array, NULL, 0);

answered Oct 23, 2012 at 7:29

Paul R

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