Still trying to figure out if there is a function in Python to get a random float value with step? Similar to randrange(start, stop, step) but for floats.
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2 Answers
import random
def randrange_float(start, stop, step):
return random.randint(0, int((stop - start) / step)) * step + start
randrange_float(2.1, 4.2, 0.3) # returns 2.4
1 Comment
Mark Dickinson
Using
int(round(...)) may be a little safer than using int(...), especially if it'll usually be the case that stop - start is close to a multiple of step. Otherwise it's difficult to predict whether stop will be a possible value or not.Just multiply for some appropriate constant in order to get integers and reverse the operation over the result.
start = 1.5
stop = 4.5
step = 0.3
precision = 0.1
f = 1 / precision
random.randrange(start*f, stop*f, step*f)/f
