經濟、哪中央標準局員工消費合作社印製 〇iS625 A7 _____B7 五、發明説明（i ) <發明背景> 測量距離之習用光電儀器，有光波測距器、三角測量法 距離感測器、雷射調變測距方式距離感測器、脈衝測距方式 距離感測器等，其應用原理不論爲何？其無法將兩個目標點加 以標示並準確地測量兩個目標點間的距離，例如習用技術是 無法在遠處準確地標示測量一棟建築物的寬度、一部車輛的 長度及一間房屋之窗戶的高度。 <發明槪述> 本發明的主要目的是硏究製造一種裝置用來準確地測量 遠方兩個目標點的距離，在整個測量過程中兩個目標點將以 雷射光束投射淸楚地標示出來，每個目標點的標示皆由兩道 來自不同方向之雷射光束苘時投射至該目標點而構成，因此 在近距離測量時<例如室內牆壁兩點），於測量完兩目標點間 距離後，可將任一雷射指示器投射鏡頭加裝點轉換線鏡片， 調整鏡片使其在牆壁上畫出一道雷射線而通過兩個目標點。 本發明的另外一個目的是提供一種測距儀器，組裝配件 力求精簡，製造容易，大幅降低製造成本。 本發明在基台上以定距離設置左右二個旋轉盤，旋轉盤 上設有內徑、外徑旋轉圈，內徑外徑旋轉圈旋轉角度可讀得， 每個旋轉圈各固定一個圓柱形雷射指示器，因此本發明將使 用四個雷射指示器以產生四道雷射光束，旋轉盤的圓心視爲 雷射光射出點。待測距離是遠方二個目標點稱左、右目標點 -3 - 本紙法尺度適用中Η國家標準（CNS ) A4规格（210 X 2的公釐） C請先閲讀背面之注意事項再填寫本頁) _'χ ,_______.訂— — 經濟部中央樣準局員工消费合作社印製 A7 _B7 _______ 五、發明説明（2 ) ，因此左、右目標點與左'右旋轉盤圓心共四點，調整基台 使四點共平面，左目標點與兩個旋轉盤的圓心三點成一三角 形稱左三角形，右目標點與兩個旋轉盤的圓心三點成一三角 形稱右三角形，左、右三角形的形成因左、右旋轉盤各有一 道雷射光束投射至左目標點及右目標點而具體成形’左'右 三角形三內角角度可藉由讀得旋轉圈之角度後計算出來’ 左、右三角形共同底邊爲左、右旋轉盤圓心間已知距雛’依 幾何三角定理左、右三角形其他二邊長度亦可計算求得’左 旋轉盤圓心與左、右目檩點共三點又構成一三角形’三角形 中的二邊如左旋轉盤圓心至左目標點距離是左三角形的邊， 左旋轉盤圓心至右目標點距離是右三角形的邊’二邊間的夾 角角度亦可計算求得，依三角餘弦定理已知三角形二邊長度 爲a、b其夾角爲θ，則第三邊長度a2+b2-2 abc^i計 算求得遠方二目標點間距離。' <發明詳細說明> 茲配合附圖詳細說明本發明之結構、動作方式、計算原 理及特徵如下：’ '附圖之簡單說明：第一圖係本發明動作及外観圖 第二W係本發明左旋轉盤之立體分解圖 第三圖係本發明俯視動作圖 第四圖係本發明計算原理示意圖 請參考第一圖在基台30的左邊建構左旋轉盤19，左旋轉盤 -4- 210χ29-τ^"~~ ~' (请先閱讀背*之注意事項再填寫本I ) 象 訂Printed by the Employees ’Consumer Cooperative of the Central Standards Bureau of Economy, iS625 A7 _____B7 V. Description of the Invention (i) < Background of the Invention > Conventional photoelectric instruments for measuring distances, including light wave rangefinders, triangulation distance sensors, mines What is the application principle of the distance sensor of radio modulation ranging method and the distance sensor of pulse ranging method? It cannot mark two target points and accurately measure the distance between the two target points. For example, conventional techniques cannot accurately mark and measure the width of a building, the length of a vehicle, and the length of a house at a distance. The height of the window. < Description of the invention > The main purpose of the present invention is to research and manufacture a device for accurately measuring the distance between two target points in the distance, and the two target points will be marked with laser beam projection during the entire measurement process. The mark of each target point is composed of two laser beams from different directions projected to the target point, so when measuring at a short distance < such as two points on the indoor wall), after measuring the two target points After the distance, any laser pointer projection lens can be equipped with a point conversion line lens, and the lens can be adjusted to draw a laser ray on the wall and pass through two target points. Another object of the present invention is to provide a distance measuring instrument, which simplifies the assembly of parts, facilitates manufacturing, and greatly reduces manufacturing costs. The invention is provided with two left and right rotating disks at a fixed distance on the base table. The rotating disk is provided with inner diameter and outer diameter rotating rings. The rotating angle of the inner diameter and outer diameter rotating rings can be read, and each rotating ring is fixed with a cylindrical shape The laser pointer, therefore, the present invention will use four laser pointers to generate four laser beams, and the center of the rotating disk is regarded as the laser light exit point. The distance to be measured is the two target points in the distance called the left and right target points-3 The standard of this paper method is applicable to the national standard (CNS) A4 specification (210 X 2 mm) C Please read the precautions on the back before filling in this Page) _'χ, _______. Order — — A7 _B7 _______ printed by the Employee Consumer Cooperative of the Central Prototype Bureau of the Ministry of Economy V. Invention description (2), therefore, the left and right target points and the center of the left and right rotating disks have a total of four points, Adjust the abutment so that the four points are coplanar. The left target point and the three center points of the two rotating discs form a triangle called the left triangle. The right target point and the three center points of the two rotating discs form a triangle called the right triangle. The left and right triangles Because the left and right rotating discs each have a laser beam projected to the left target point and the right target point, the specific shape of the 'left' right triangle three internal angles can be calculated by reading the angle of the rotating circle 'left and right The common base of the triangle is the known distance between the center of the left and right rotating discs. According to the geometric triangle theorem, the lengths of the other two sides of the left and right triangles can also be calculated and calculated.The center of the left rotating disc and the left and right purlin points are three points. triangle 'The distance between the center of the left rotating disk and the left target point is the side of the left triangle, and the distance between the center of the left rotating disk and the right target point is the side of the right triangle.' The angle between the two sides can also be calculated and calculated according to the cosine Theorem knows that the length of the two sides of the triangle is a and b and the included angle is θ, then the length of the third side a2 + b2-2 abc ^ i is calculated to find the distance between the two target points in the distance. '< Detailed description of the invention > The structure, operation mode, calculation principle and features of the present invention are described in detail with the accompanying drawings as follows:' 'Brief description of the drawings: the first figure is the action of the present invention and the second W series The three-dimensional exploded view of the left rotating disc of the present invention. The third figure is the top action diagram of the present invention. The fourth figure is the schematic diagram of the calculation principle of the present invention. Please refer to the first figure to construct the left rotating disc 19 on the left side of the base 30. ^ " ~~ ~ '(Please read the notes on the back * and then fill out this I)
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III G13625 a7 B7 — · | 五、發明説明（y 19上有外徑旋轉圈10及內徑旋轉圈u，左外徑旋轉圈10上 固定左外徑雷射指示器12，固定方式是將左外徑雷射指示器12 利用其外緣鏍紋(未圖示)插入圓柱奢筒14再緊密旋轉結合，左 外徑旋轉圈10外側邊刻印有角度刻度16，左旋轉盤19下的 對準箭頭17是用來對準判讀左外徑雷射指示器12的旋轉角度 ，旋轉角度是以三點鐘方向爲零度反時鐘方向起算，左內徑旋 轉η是可自由旋轉的圓圈結構，其所圍的角度刻盤is是固定 不旋轉，左內徑旋轉圈Π設有圓柱套筒15用來固定左內徑雷 射指示器13，圓柱套筒15上的對準箭頭31是用來當左內徑雷 射指示器13旋轉時對準角度刻盤I8以判讀其旋轉角度’左外 徑雷射指示器12所發射的雷射光束依循雷射投射路徑前 進，左內徑雷射指示器13所發射的雷射光束依循雷射投射路徑 131前進，兩路徑延長線相交於左角度刻盤I8的圓心(未圖示）。 右旋轉盤29的結構和左旋轉盤19是一樣的，其差別只是右 外徑旋轉圈20與右內徑旋轉圈21的旋轉角度算法是以九點鐘 方向爲零度順時鐘起算’本發明四道雷射光束較佳投射方式 是左外徑雷射指示器12與右外徑雷射指示器22所投射雷射 光束投射到左目標點（未圖示），左內徑雷射指示器13與右內 徑雷射指示器23所投射雷射光束投射到右目標點(未圖示）。 第二圖係本發明左旋轉盤19之立體分解圖，因左右兩旋 轉盤之立體分解圓是一樣的，所以只繪左旋轉盤I9加以說明 ，左旋轉盤19內設有圓柱體181用來套接左內徑旋轉圈11， ____ __________-— -—___ 本紙張尺度適用中國國家標準（CNS ) Α4规格（2丨〇'乂297公董） ....... 11'» (請先聞讀背面之注意事項再填寫本頁} «—In n^— nn i -: -‘ p·* —m —'_1 - - - - - I — J - Ί *=IU1 nn II- - -- _1-· vs.-15 經濟部中央標準局员工消費合作社印家 —m Hu ml 1— fill —^n 313625 A7 B7 經 濟 部 中 央 梂 準 Μ 員 工 消 費 入 杜 印 製 五、發明説明（4 ) 以作爲左內徑旋轉圈11的支撐與轉軸，圓柱體1S1上的突出 圓盤是左角度刻盤18，其突出的厚度與左內徑旋轉圈11的厚 度是一致的，左旋轉盤的外圍圓壁ΙΜ是用來套接左外徑 旋轉圈10 ’以作爲左外徑旋轉圈10的支撐與轉軸，左外徑 雷射指示器12與左內徑雷射指示器B是一般筆型市售雷射指 示器在其內端鑽刻有鏍紋34、35以便與外徑圓柱套筒14及內 徑圓柱套筒I5經由旋轉緊密結合固定。 請參閱第三圖與第四圖，左外徑雷射指示器I：2與右外徑 雷射指示器22所發射的雷射光束同時投射到左目標點Α5Θ， 因此左旋轉盤圓心C52、右旋轉盤圓心1>53及左目標點A5〇成 三角形AACD，同理左內徑雷射指示器B與右內徑雷射指示 器23所發射的雷射光束同時投射到右目標點B51，左旋轉盤 圓心CM、右旋轉盤圓心D53及右目標點B51成三角形ABCD ，AACD與ABCD以左旋轉盤圓心C52與右旋轉盤圓心D53間 距離爲其共同底邊CD36，AACD的內角ZDCA爲左外徑雷射 指示器12的旋轉角度0b43，AACD的另一內角ZCDA爲右外徑 雷射指示器22的旋轉角度θ。44，線段CA37爲左外徑雷射指 示器12的投射路徑亦是AACD的邊，線段D A 38爲右外徑雷 射指示器22的投射路徑亦是AACD的邊；同理ΔΒ(：Ι>的內角 ZDCB爲左內徑雷射指示器13的旋轉角度6a 42 ’ ABCD的另 —內角ZCDB爲右內徑雷射指示器23的旋轉角度45，線段 C B 39爲左內徑雷射指示器I3的投射路徑亦是ABCD的邊，線 (CNS )八4絲（210X 297公釐） (請先閱讀背面之注意事項再填寫本頁) --訂 丨 V - -1 - - - -I...... I I - · • fn I— -- I - t«'- - 一 - - A7 B7St qi < \ I ^ -II ............ ml fm ntn .......... III G13625 a7 B7 — · | V. Invention Description (y 19 has an outer diameter rotating ring 10 and an inner diameter rotating ring u, a left outer diameter laser indicator 12 is fixed to the left outer diameter rotating ring 10, and the fixing method is to use the left outer diameter laser indicator 12 to the outside The edge screw (not shown) is inserted into the cylindrical luxury tube 14 and then tightly rotated and combined. The left outer diameter rotating ring 10 is engraved with an angular scale 16 on the outer side. The alignment arrow 17 under the left rotating disk 19 is used to align and interpret the left outer The rotation angle of the diameter laser indicator 12, the rotation angle is calculated from the direction of zero at three o'clock and the counterclockwise direction, the left inner diameter rotation η is a freely rotating circle structure, and the surrounding engraving disc is fixed and not rotating , The left inner diameter rotating ring Π is provided with a cylindrical sleeve 15 for fixing the left inner diameter laser indicator 13, and the alignment arrow 31 on the cylindrical sleeve 15 is used to adjust the left inner diameter laser indicator 13 when it rotates. The quasi-angle engraving disc I8 is used to determine the rotation angle. The laser beam emitted by the left outer diameter laser indicator 12 follows the laser projection path, and the laser emitted by the left inner diameter laser indicator 13 The beam follows the laser projection path 131, and the extension lines of the two paths intersect at the center of the left-angle disc I8 (not shown). The structure of the right rotary disk 29 is the same as that of the left rotary disk 19, and the only difference is that the right outer diameter rotates The rotation angle algorithm of the ring 20 and the right inner diameter rotating ring 21 starts from zero clockwise at nine o'clock. The preferred method for projecting four laser beams of the present invention is the left outer diameter laser indicator 12 and the right outer diameter laser The laser beam projected by the laser pointer 22 is projected to the left target point (not shown), and the laser beam projected by the left inner diameter laser pointer 13 and the right inner diameter laser pointer 23 is projected to the right target point (not shown) The second figure is a three-dimensional exploded view of the left rotating disk 19 of the present invention. Since the left and right rotating disks have the same three-dimensional exploded circle, only the left rotating disk I9 is depicted for illustration. The left rotating disk 19 is provided with a cylinder 181 for Socket left inner diameter rotating circle 11, ____ __________-— -—___ This paper scale is applicable to the Chinese National Standard (CNS) Α4 specification (2 丨 〇'297297) ....... 11 '»(please Read the precautions on the back first and then fill in this page} «—In n ^ — nn i -:-'p · * —m —'_ 1-----I — J-Ί * = IU1 nn II---_1- Hu ml 1 — fill — ^ n 313625 A7 B7 Central Ministry of Economics □ Employee consumption into Du printed 5. Description of invention (4) Used as the support and rotation axis of the left inner diameter rotating ring 11, the protruding circle on the cylinder 1S1 The disc is a left-angle engraved disc 18, and its protruding thickness is the same as the thickness of the left inner-diameter rotating ring 11. The peripheral round wall of the left rotating disc is used to sleeve the left outer-diameter rotating ring 10 'as the left outer-diameter rotation The support and rotation shaft of the ring 10, the left outer diameter laser indicator 12 and the left inner diameter laser indicator B are general pen-type commercially available laser indicators with rivets 34, 35 drilled on their inner ends to match the outer diameter The cylindrical sleeve 14 and the inner diameter cylindrical sleeve I5 are tightly fixed by rotation. Please refer to the third and fourth figures, the laser beams emitted by the left outer diameter laser indicator I: 2 and the right outer diameter laser indicator 22 are simultaneously projected to the left target point Α5Θ, so the center of the left rotating disk C52, right The center of the rotating disk 1> 53 and the left target point A5〇 form a triangle AACD. Similarly, the laser beams emitted by the left inner diameter laser indicator B and the right inner diameter laser indicator 23 are simultaneously projected to the right target point B51, left Turntable center CM, right rotary center D53 and right target point B51 form a triangle ABCD, AACD and ABCD take the distance between left rotary center C52 and right rotary center D53 as their common base CD36, and the inner angle ZDCA of AACD is the left outer diameter The rotation angle 0b43 of the laser pointer 12 and the other inner angle ZCDA of the AACD are the rotation angle θ of the right outer diameter laser pointer 22. 44, the line segment CA37 is the projection path of the left outer diameter laser indicator 12 is also the side of AACD, and the line segment DA 38 is the projection path of the right outer diameter laser indicator 22 is also the side of AACD; the same reason ΔΒ (: Ι > The inner angle ZDCB is the rotation angle 6a 42 'ABCD of the left inner diameter laser indicator 13-the inner angle ZCDB is the rotation angle 45 of the right inner diameter laser indicator 23, and the line segment CB 39 is the left inner diameter laser indication The projection path of the device I3 is also the edge of the ABCD, the line (CNS) eight 4 wires (210X 297 mm) (please read the precautions on the back before filling this page) --Subscribe 丨 V--1----I ...... 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五、發I 輕濟部中夬棣率局員工消貧合作'社¥製·Fifth, I issued the Ministry of Light Economy, Ministry of Economic Affairs and Development Bureau staff poverty alleviation cooperation 'community ¥ system ·
段DB4〇爲右內徑雷射指示器23的投射路徑亦是^bcd的邊。 左目標點A5〇、右目標點及左旋轉盤圓心C52亦形成三角 形AACB’AACB的兩邊CA與CB以及其夾角/人〇3爲0646， 應用三角餘弦定理可得遠方兩目標點間距離AB，數學計算過 程如下： 左旋轉盤圓心C52作垂直延長線交線段DA於ρ 右旋轉盤圓心D53作垂直延長線交線段CB於e 直角三角形ACDF中CF=CD*5*<0c ______________⑴（已知CD ) 直角三角形ACFA中eg=0b-〇/2-ee) 所以 CAsCF+S^Gg): CF*«SVe[eb-(7i/2-ec)]= CF*(?4e(eb+0c)---(2) (1)式代入(2)式得 CA= 直角二角形ACDE 中 CE=CD*办» DE= CD*5V»0a (3) 直角三角形ABED中011=0七(71/2-0&) 所以 EB=DE*&*eh= DE*&4ed+ea-7t/2].........—......._(4) (3)式代入(4)式得 EB=CD*汾《ea*^H^d+ea-Tt/2] CB=CE+EB= CD*[^6a+ ^θ3*^(θ^+θ3-π/2)] 遠方兩目標點距離 AB=[CA2+CB2-2*CA*CB*<j<^ee] 1/2 可以設計微處理電路與程式利用上述結果只要輸入ea、、 Qc&ed(CD長度爲已知內建値)立即顯示CA、CB及AB之距離 ’則不但可得兩目標點距離，測量者至兩目標點距離一倂求 得。 7. 國國家橾率（CNS ) A4規格（210X297公釐） (請先閱讀背面之注意事項再填寫本頁) ψ\ "士农--- 訂 UM.The segment DB40 is the projection path of the right inner diameter laser indicator 23 and is also the side of ^ bcd. The left target point A5〇, the right target point and the center of the left rotating disk C52 also form the triangles AACB'AACB. The two sides CA and CB and their angle / person 〇3 is 0646. Applying the triangle cosine theorem can get the distance AB between the two target points in the distance, mathematical The calculation process is as follows: the center of the left rotating disk C52 is the vertical extension line intersection line DA at ρ, the center of the right rotating disk D53 is the vertical extension line intersection line CB in e right-angle triangle ACDF CF = CD * 5 * < 0c ______________ ⑴ (known CD) Right-angled triangle ACFA eg = 0b-〇 / 2-ee) So CAsCF + S ^ Gg): CF * «SVe (eb- (7i / 2-ec)) = CF * (? 4e (eb + 0c)- -(2) (1) Substitute (2) into CA = right-angled square ACDE in CE = CD * do »DE = CD * 5V» 0a (3) Right-angled triangle ABED 011 = 0 seven (71 / 2- 0 &) So EB = DE * & * eh = DE * & 4ed + ea-7t / 2] .........--......._ (4) (3) Substituting (4) into EB = CD * 汾 《ea * ^ H ^ d + ea-Tt / 2] CB = CE + EB = CD * [^ 6a + ^ θ3 * ^ (θ ^ + θ3-π / 2) ] The distance between the two target points in the distance AB = [CA2 + CB2-2 * CA * CB * < j < ^ ee] 1/2 The micro-processing circuit and program can be designed to use the above results as long as the input ea, Qc & ed (CD length (It is a known built-in value) immediately displays the distance between CA, CB and AB 'The distance between the two target points is not only available, but also the distance from the surveyor to the two target points. 7. The national rate (CNS) A4 specification (210X297mm) (Please read the notes on the back before filling this page ) ψ \ " Shennon --- Order UM.