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Questions tagged [factorization]

For questions about factorization, the decomposition of mathematical objects (e.g. natural numbers, polynomials) into products of smaller objects (e.g. primes, lower degree polynomials).

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Factorization of integers of special forms are of both theoretical interest and cryptographic implications. Experimentally we found a seemingly "large" set of integers for which a divisor ...
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Let $x,y,X,Y,D>1$ be positive integers. Let $X^D+Y^D=n$ and assume $Y>X^{D/(D-1)}$. Conjecture 1 $Y=\lfloor n^{1/D}\rfloor$ and $X=(n-Y^D)^{1/D}$ Let $Y^D-X^D=n$ and assume $Y>X^{D/(D-1)}$. ...
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Let $p,C$ be positive integers and assume $0 < C< \sqrt{p}$ Let $n=p (p+C) $ and assume $n$ is odd. Conjecture 1 Given $n$ we can find $p,p+C$ with complexity computing two integer square roots ...
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Let $p,q$ be positive integers and $ 0 < C < 1$ real. Let $n=p q$ and assume $ 0 < q - p < p^C$ Q1 Is there $C$ such that given $n$ we can factor it (find $p,q$) in polynomial in $\log{p}$...
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From our preprint On factoring integers of the form $n=(x^D+1)(y^D+1)$ and $n=(x^D+a_{D-2}x^{D-2}+\cdots+ a_0) (y^D+b_{D-2}y^{D-2}+ \cdots+b_0)$ with $x,y$ of the same size. We got plausible ...
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This question is inspired by the classical behavior of Euler’s polynomial $$ \mathbf{f(x) = x^2 - x + 41}, $$ which is well-known for producing prime values for integer inputs $x = 0$ to $39$, and is ...
Isaac Brenig's user avatar
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This conjecture is based on computational exploration of quadratic polynomials associated with imaginary quadratic fields of class number one. Let us define: • For a polynomial $f(x) \in \mathbb{Z}[...
Isaac Brenig's user avatar
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There is a nice family of cubic polynomials with galois group C3 described here: https://math.stackexchange.com/questions/4684769/parametric-family-of-cubics-with-galois-group-c-3 (There are some ...
Oisin Robinson's user avatar
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The tridiagonal Toeplitz matrices $$\begin{pmatrix} a & b & & \\ c & \ddots & \ddots \\ & \ddots & \ddots & b \\ & & c ...
Oliver Bukovianský's user avatar
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Example: 72 has the following divisors: 1, 2, 3, 4, 6, 8, 9, 12, 18, 24, 36, 72. The median (middle) divisors are 8 and 9. Provided we already have the prime factors of a number x, what would be an ...
rotatingmind's user avatar
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I asked this question on MSE here Let $ f_n $ be the $ n $-th Faulhaber polynomial. In this question, I observed the following divisibility properties: If $ n $ is even, then $ f_n $ is divisible by ...
pie's user avatar
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Define polynomials $f_n(q)$ by $f_1(q)=q^2+q$ and $$ f_{n+1}(q) = f_n(q)(f_n(q)+2^{2^{n-1}-1}),\ n\geq 1. $$ Then for $n\geq 3$, it seems to be the case that $f_n(q)+2^{2^{n-1}-1}$ factors (over $\...
Richard Stanley's user avatar
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There are various rumours about links between strongly ambiguous ideals and factors of the discriminant of a number field. Illustrating this question by way of a concrete example, let $$f = x^7 + 9x^6 ...
Oisin Robinson's user avatar
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We got a fast probabilistic algorithm for factorizations of univariate polynomials of special form modulo $N$ and would like to know if it is known or trivial. Let $N$ be composite integer with ...
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I have encountered a polynomial that almost looks like a product of two polynomials of the form $(x+y)^d$, but not quite... The exact polynomial looks like this: $$ \sum_{0 \leq i_1 \leq d_1} \sum_{0 \...
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Quite some ago, the following question was asked on this site: How hard is it to compute the number of prime factors of a given integer? Terence Tao gave a very interesting answer that involves number ...
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For a given integer $N = p\cdot q$ with $p \leq q$, if $q$ is close to $N^{1/2}$, say $$N^{1/2} \leq q \leq N^{1/2} + (4N)^{1/4}$$ then $p,q$ can be recovered very quickly using Fermat's factoring ...
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Let $N=p q$ and let $D=\frac{\log{q}}{\log{p}} > 1$. Conjecture 1 There exist positive real constant $A$ depending only on $D$ such that given integer $r$ in the range $[q-q^{\frac{D-1}{D}},q+q^{\...
joro's user avatar
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Related to open problem and this question. Let $N=p q$ be integer with unknown factorization. We are looking for an answer which can be used in factorization algorithm, so factoring $N$ is not allowed....
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Short version. What upper bounds are known, for the number of divisors of Mersenne numbers? Long version. Studying the structure of the factors of $M_n = 2^n - 1$ appears to be an active and difficult ...
Niel de Beaudrap's user avatar
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We got a probabilistic integer factorization algorithm and experimental evidence with large integers given bounds for one factor. Let $D \ge 2$ be real number and let $p,q$ be primes and $N=pq$. ...
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Is it any easy to factor $p-1$ when $p$ is a prime compared to general factorization problem? What about when $2p+1$ is also a prime?
Turbo's user avatar
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Let $R$ be a commutative ring. Call a nonempty subset $F$ of $R$ a factroid if it is closed under sums and factors. That is: If $a,b \in F$, then $a+b \in F$, and If $a,b \in R$ with $a\in R$ ...
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Given a prime $p>2$, let $x$ and $y$ be real numbers such that $x>y>0$ and $$ \begin{equation} x^p-y^p=(x-y)^p+pxy(x-y)R \tag{1} \label{eq:one} \end{equation} $$ where $R$ is a bivariate ...
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As usual, call a positive integer $y$-smooth if it has no prime factors greater than $y$. Write $S(x,y)$ for the set of $y$-smooth integers $\leq x$. Write $R(x,y)$ for the set of quotients $\{a/b: a,...
H A Helfgott's user avatar
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An integer is said to be $y$-smooth if it has no prime factors $>y$. Let $y$ be "medium sized", meaning $(\log x)^{1+\epsilon} < y < \exp((\log x)^{2/3})$ or so. (Why this range of ...
H A Helfgott's user avatar
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Two spaces $X$ and $Y$ are said to be rationally homotopy equivalent, written $X \sim_{\mathbb{Q}} Y$, if their rationalizations $X_{\mathbb{Q}}$ and $Y_{\mathbb{Q}}$ are homotopy equivalent. Moreover,...
Baylee Schutte's user avatar
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For odd integer $n$ define the function $$ J(n)=(2^{\varphi(n)}-1) \bmod{n^2}$$ $J(n)$ is integer in $[0,n^2-1]$ and it is divisible by $n$. Integer $n$ is Wieferich number iff $J(n)=0$ and if $n$ is ...
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Let $F$ be a field, and let $P(X_1,\dots,X_m)$, $Q(X_1,\dots,X_m) \in F[X_1,\dots,X_m]$ be two coprime polynomials. Consider $n$ new polynomials $R_1(Y_{1,1},\dots,Y_{1,n}) \in F[Y_{1,1},\dots,Y_{1,n}]...
Maurizio Barbato's user avatar
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Does every finite group $G$ have a factorization $G=H_1\cdots H_k$ where the $H_i$ for $1\le i\le k$ are solvable subgroups of $G$ and $|G|=|H_1|\cdots |H_k|$ (equivalently, every element of $G$ is ...
Tom WIlde's user avatar
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We got an algorithm and toy implementation of integer factoring algorithm based on smooth class number of quadratic fields. It is close to the elliptic curve factorization method (ECM) and succeeds if ...
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3 votes
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Let $n$ be positive integer with unknown factorization and $A$ integer with known factorization. According to pari/gp developers pari can efficiently find all solutions of: $$x^2+n y^2=A \qquad (1)$$ ...
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In this and this question we show that if $p=27a^2+27a+7$ is prime, then the order of the elliptic curve $y^2=x^3+2$ modulo $p$ is either $p$ or $p+2$. Q1 Can we unconditionally show that the order ...
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In this two page note we give efficient probabilistic algorithm for factoring bivariate polynomials in composite characteristic assuming the solution is unique and we would like to test the algorithm ...
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We found and implemented in sage efficient algorithm for factoring bivariate polynomials modulo composite modulus assuming the solution is unique up to a constant factor. More formally let $K=\mathbb{...
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This may help: A080670 A195265 Define $f(n)$ as this: Take a number $n$, and split it into its prime composition using $^$ and $×$. Now remove all $^$ and $×$, you get a new number, this is $f(n)$ (...
look at me's user avatar
13 votes
2 answers
681 views

Let $n=p_1^{a_1}\cdots p_k^{a_k}$ be the prime power factorization of the positive integer $n$, with $p_1<\cdots<p_k$ and $a_i>0$. Define $\kappa(n)=(a_1,\dots,a_k)$, the composition type of $...
Richard Stanley's user avatar
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I have some number $N$ and some integer $k>0$. I want to know what fraction of numbers up to $N$ have more than $k$ prime factors. (In my application, with repetition, but the $\omega$ version is ...
Charles's user avatar
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It is well-known that if we pass from a UFD to a new ring where we have factored one of the primes, it does not need to stay a UFD. The classic example is passing from $\mathbb{Z}$ to $\mathbb{Z}[\...
Pace Nielsen's user avatar
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Suppose we want to build a primality testing algorithm for the numbers limited to the set $A =\{1, ..., 2^n\}$ and $n$ is reasonably large. The prime-number theorem tells us that there are ...
user1747134's user avatar
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1 answer
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Let $n\in\mathbb{N}$ and $P_{n}$ is $0,1$-polynomial whose coefficients are binary digits of $n$. Let $Q_{1}(x) \cdot Q_{2}(x) \cdots Q_{m}(x)$ - polynomial factorization (over integers) of $P_{n}$. ...
Denis Ivanov's user avatar
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So, today I came up with a method for factoring polynomials whose coefficients are either $-1$ or $1.$ Let me explain with examples. Example No. 1. Factorize $P(x)=x^8+x^7+1$ Solution. It is known ...
Ivan Borisyuk's user avatar
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Being interested in these polynomials, would like to clarify one small observation. Let $n\in\mathbb{N}$ and $P_{n}$ is $0,1$-polynomial whose coefficients are binary digits of $n$. Let $n$ has prime ...
Denis Ivanov's user avatar
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Happy New Year, MO community! We need someone expert in Generalized Continued Fractions (GCFs), with a deep knowledge of the GCFs’ convergence properties, to solve the following problem. PROBLEM ...
Monk's user avatar
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In factorization, like integer factorization, you start with an integer and end up with a kind-of list of pairs of other elements, namely the factors. I want to explore the "Co-ness" of this....
Ben Sprott's user avatar
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2 votes
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Given a polynomial $f(x) \in \mathbb{R}[x] = \mathbb{R}[x_{1},\dots,x_{n}]$. We say $f(x)$ is sum of squares(SOS) if there are polynomials, $p_{1},\dots,p_{k}$ such that $f = p_{1}^{2} + \dots+p_{k}^{...
patchouli's user avatar
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3 answers
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Edit [2023 Dec 7]: One of my specific wonders, along with that of students, is around when a recursive formula might have – or be expected to have – an explicit or closed formula. What is the ...
Benjamin Dickman's user avatar
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Suppose a square $n\times n$, dense matrix $A^{\text{old}}$ has been factorized into $L^{\text{old}}$ and $U^{\text{old}}$ components by performing a LU decomposition $A^{\text{old}} = L^{\text{old}}U^...
Alex Joe's user avatar
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I want to represent $\sin(x)-\dfrac{1}{\sqrt{2}}$ as a product of it's zeroes According to the Weierstrass factorization theorem, the sine function can be represented as a product of its factors: $$\...
LithiumPoisoning's user avatar
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Let $G$ be a graph on $n$ vertices. Let $A$ be the adjacency matrix of $G$ (i.e., rows and columns of $A$ are indexed by vertices of $G$, and the $(v,w)$ entry of $A$ is $1$ if $(v,w)$ is an edge in $...
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