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Questions tagged [divisors-multiples]

For questions on divisors and multiples, mainly but not exclusively of integers, and related and derived notions such as sums of divisors, perfect numbers and so on.

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A positive integer $n$ is weird if it is abundant and cannot be expressed as a sum of distinct proper divisors of $n$. As in the case of perfect numbers, all weird numbers currently known are even (in ...
G. Melfi's user avatar
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Factorization of integers of special forms are of both theoretical interest and cryptographic implications. Experimentally we found a seemingly "large" set of integers for which a divisor ...
joro's user avatar
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82 votes
10 answers
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I've been comparing the sequence of the Least Common Multiple of the first $n$ integers, $L_n = \text{lcm}(1, 2, \dots, n)$, with the sequence of Highly Abundant Numbers (HA). The two sequences in ...
José Damián Espinosa's user avatar
4 votes
1 answer
335 views

The sequence of colossally abundant (CA) numbers, $a(n)$ (OEIS A004490), consists of positive integers that maximize the ratio $\frac{\sigma(m)}{m^{1+\epsilon}}$ for some $\epsilon > 0$. A known ...
José Damián Espinosa's user avatar
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Motivated by a problem concerning the existence of quasi-periodic solutions in dynamical systems, I encountered a number-theoretic question that appears somewhat unusual. I would like to know whether ...
Xueping's user avatar
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(cross-posted from Math Stack Exchange, as it did not get any comment or answer, even after being bountied) Let $S_1=\sum_{i=0}^{n} p^i = \frac{p^{n+1}-1}{p-1}$ and $S_2=\sum_{i=0}^{m} q^i = \frac{q^{...
Juan Moreno's user avatar
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107 views

Let $P(x)$ be a polynomial in one variable with coefficients in a number field $K$. Let $b \geq 2$ be a positive integer. Suppose $P(x^b)$ is irreducible. Let $F(x)$ and $R(x)$ be polynomials with ...
Johnny T.'s user avatar
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Inspired by this question and answer, I want to apply Bang's lemma to a number theoretic setting: Bang's lemma for p.d. kernels: Let $k : X \times X \rightarrow \mathbb{R}$ be a positive definite ...
mathoverflowUser's user avatar
52 votes
2 answers
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Let $a,b$ be positive integers. Because binomial coefficients are integers, we know that $a!b!$ divides $(a+b)!$. For particular $a$ and $b$ there may be a gap $g$ with a tighter result, so $a!b!$ ...
Bill Bradley's user avatar
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3 votes
1 answer
199 views

A well-known application of the pigeonhole principle, due to Erdős, says that every subset of $\{1,2,\dots, 2n\}$ of size $n+1$ contains two distinct elements dividing each other. This remark can be ...
Jens Reinhold's user avatar
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Let $\sigma_0(n)$ be from number theory, i.e. the total number of divisors of an integer $n$. Let $p_n$ denote the $n$th prime number. Let $S =$ the set of prime numbers $p \in 4\Bbb{Z} + 1$ such ...
Luna's Chalkboard's user avatar
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Question: Is there a Carmichael number $n$ satisfying $\sigma(n)\equiv0\pmod{n+1}$ ? Motivation: It can be proved that a positive integer $n$ simultaneously satisfying $n\equiv1\pmod{\phi(n)}$ and $\...
Tong Lingling's user avatar
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Let $N=p q$ and let $D=\frac{\log{q}}{\log{p}} > 1$. Conjecture 1 There exist positive real constant $A$ depending only on $D$ such that given integer $r$ in the range $[q-q^{\frac{D-1}{D}},q+q^{\...
joro's user avatar
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The computer found this. Let $n$ be a positive integer. Up to $n=200$ we have: $$\frac{\varphi(2^n-1)}{n}=\frac{2^{\varphi(2^n-1)}-1 \bmod (2^n-1)^2}{2^n-1}. \tag{1}\label{483144_1}$$ Q1 Is \eqref{...
joro's user avatar
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I am looking for a closed form for this function $\Lambda:\mathbb{Q}^+\to\mathbb{R}^+$: $$\Lambda(q) = \sum_{m,n\geq 1}\left(\frac{q\wedge\frac{m}{n}}{q\vee\frac{m}{n}}\right)^\alpha\left(\frac{m \...
Alexandre's user avatar
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Definitions: Here I present a novel conjecture using basic mathematical tools like the sum of the divisors of an integer $n$ called $\sigma(n)$, the sum of the squares of the positive divisors of $n$ ...
Sulfura's user avatar
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Fix any positive integer $n\in\mathbb{Z}^+,$ and consider the function $f_n : \mathbb{Z}^+\setminus\{n\}\to\mathbb{Z}^+$ given by $$f_n(t)=\sigma_0(n)+\sigma_0(t)-2\sigma_0(\gcd(n, t)),$$ where $\...
Bumblebee's user avatar
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12 votes
3 answers
797 views

When using the standard Euclidean algorithm to compute the greatest common divisor of a pair of relatively prime positive integers, the integer $2$ sometimes arises and sometimes does not. For example,...
Joel Louwsma's user avatar
1 vote
0 answers
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This question was inspired by this MSE question. In MSE, it is shown that $$n - \varphi(n) = (2^{p-1})^2$$ if $n = {2^{p-1}}(2^p - 1)$ is an even perfect number. Here is my question in this post: Is $...
Jose Arnaldo Bebita Dris's user avatar
2 votes
1 answer
251 views

Let $p$ be a prime, $a \neq 0$ an integer, let $M,N \gg 1$ and let $\psi,\eta$ be some fixed Schwartz functions. Would you know of any references in the literature where upper bounds for sums such as $...
user152169's user avatar
-4 votes
2 answers
285 views

(Preamble: Andy Putman asserts, in the comments, that MO policy prohibits "requests to check completeness of proofs". I have therefore trimmed down my original question to the bare ...
Jose Arnaldo Bebita Dris's user avatar
2 votes
1 answer
218 views

My present question is as is in the title: If $p^k m^2$ is an odd perfect number with special prime $p$, then must $m^2 - p^k = s^2 - t^2$ hold for some $s$ and $t$? It is known that $m^2 - p^k$ is ...
Jose Arnaldo Bebita Dris's user avatar
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0 answers
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Denote the classical sum of divisors of the positive integer $x$ by $\sigma(x)=\sigma_1(x)$. My question is as is in the title: If $p^k m^2$ is an odd perfect number with special prime $p$, is it ...
Jose Arnaldo Bebita Dris's user avatar
12 votes
1 answer
2k views

$n$ is a natural number $>1$, $\varphi(n)$ denotes the Euler's totient function, $P_n$ is the $n^\text{th}$ prime number and $\sigma(n)$ is the sum of the divisors of $n$. Consider the expression: $...
Craw Craw's user avatar
7 votes
2 answers
818 views

I’m interested in the function $\tau_n:\mathbb{N}\to\{1,2,3,\cdots, n\}$ defined by $$\tau_n(x)=\sum_{k=1}^n \mathbf{1}_{k\mid x},$$ the number of divisors of $x$ which are at most $n$. Question 6 of ...
TheBestMagician's user avatar
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1 answer
522 views

Let $N = p^k m^2$ be an odd perfect number with special prime $p$ satisfying $p \equiv k \equiv 1 \pmod 4$ and $\gcd(p,m)=1$. Let $\sigma(z)$ denote the classical sum of divisors of the positive ...
Jose Arnaldo Bebita Dris's user avatar
0 votes
1 answer
155 views

What can be said about the quantity $$\gcd(N/q^{\alpha},\sigma(N/q^{\alpha}))$$ where $N$ is an odd perfect number and $q^{\alpha} \parallel N$? In particular, can one prove that it is always greater ...
Jose Arnaldo Bebita Dris's user avatar
4 votes
1 answer
269 views

Question. Do there exist two multisets $A, B$ consisting of positive integer numbers such that $|A|$ and $|B|$ have different parity and $$ \prod_{n\in A}(n + \sqrt{n^2 + 1}) = \prod_{m\in B}(m + \...
Pavel Gubkin's user avatar
8 votes
1 answer
245 views

I put forward a hypothesis in number theory, it is as follows.$ \sigma_1(n)=\sigma_1(m)=p$, where $\sigma_1$ is the divisor sum function, $n,m\in \mathbb N$, and $p$ is prime. I recently noticed and ...
Arsen Vardanyan's user avatar
2 votes
0 answers
215 views

Can anyone point me to a reference for the main term when approximating the exponential sum of the 3-fold divisor function? Specifically I want the main term in $$\sum _{n\leq x}d_3(n)e\left (an/q\...
tomos's user avatar
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2 votes
2 answers
258 views

For a non zero rational $r=p/q$ ($p,q\in\mathbb Z$ coprimes), define the height of $r$ by $\mathrm{ht}(r)=\max(|p|,|q|)$ (by convention $\mathrm{ht}(0)=0$). For a polynomial $P\in\mathbb Q[X]$, define ...
joaopa's user avatar
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8 votes
2 answers
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Let $\sigma_0(n)$ be the divisor counting function $$\sigma_0(n) = \sum_{d \vert n} 1.$$ I'm interested in the convolution sum $$ S(n) := \sum_{k=1}^{n-1} \sigma_0(k) \sigma_0(n-k)$$ I ran some quick ...
Adithya Chakravarthy's user avatar
9 votes
1 answer
690 views

Let $\sigma_0(n)$ be the divisor counting function: $$\sigma_0(n) = \sum_{d \vert n} 1.$$ I ran some numerical experiments that showed when $p$ is prime, the function $\sigma_0(n)$ is equidistributed ...
Adithya Chakravarthy's user avatar
1 vote
0 answers
199 views

In what follows, we let $N = r^s u^2$ be an odd perfect number given in Eulerian form, i.e. $r$ is the special prime satisfying $r \equiv s \equiv 1 \pmod 4$ and $\gcd(r,u)=1$. In this preprint, ...
Jose Arnaldo Bebita Dris's user avatar
4 votes
0 answers
115 views

I've asked nine months ago this question on Mathematics Stack Exchange with identifier 4430381 and same title. There is not answer for this question on Mathematics Stack Exchange, I wondered if this ...
user142929's user avatar
3 votes
1 answer
1k views

The OEIS sequence https://oeis.org/A327265 starts: $$1, 2, 5, 11, 19, 31, 51, 89, 123, 151, 179, 181, 180, 365, 634, 657, 656, 655.$$ $\mathrm{A327265}(n)$ is the smallest $k$ such that $\mathrm{...
user avatar
0 votes
1 answer
197 views

Let $N = q^k n^2$ be an odd perfect number with special prime $q$ satisfying $q \equiv k \equiv 1 \pmod 4$ and $\gcd(q,n)=1$. Denote the classical sum of divisors of the positive integer $x$ by $\...
Jose Arnaldo Bebita Dris's user avatar
3 votes
0 answers
125 views

Is the following Open question or Conjecture already known, or eventually settled ? Open question : For sufficiently large $x$ there is at least a positive integer in the interval $[x,x+\log^2(x)]$ ...
G. Melfi's user avatar
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4 votes
2 answers
527 views

It is well known that if $p$ is prime, Stirling numbers of the first and second kind, $s_1(p,k)$ and $s_2(p,k)$, are divisible by $p$ if $1<k\le p-1$ (Lagrange ; easiest is working in $\mathbb F_p$ ...
Feldmann Denis's user avatar
4 votes
0 answers
208 views

This is cross-posted from math.stackexchange. While making some computation, I stumbled upon a curious relation among some binomial coefficients. Consider the sequence of binomial coefficients $a(k,n)$...
Fabius Wiesner's user avatar
1 vote
2 answers
240 views

In a commutative ring $R$, when does the assumption $r_i\mid r$ for $1\le i\le n$ imply $\prod_{1\le i\le n} r_i\mid r$ (when $r_i$ are fixed)? Does there exist any criterion for this implication that ...
Mikhail Bondarko's user avatar
4 votes
1 answer
330 views

Let $\sigma(n)$ be the sum of the divisors of $n$. Is it always true that if $n$ is odd, that $$n\mid\sum_{k=1}^{\frac{n-1}{2}}k^2\sigma(k)\sigma(n-k)?$$ I have checked this up to $n=100$, and I ...
JoshuaZ's user avatar
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1 vote
0 answers
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The Shapiro inequality is the statement that if $x_1, x_2, \dots, x_n$ are positive, with $x_{n+1}=x_1, x_{n+2}=x_2$, then $$\sum_{i=1}^{n} \frac{x_i}{x_{i+1}+x_{i+2}} \geq \frac{n}{2}.$$ This can be ...
JoshuaZ's user avatar
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8 votes
1 answer
420 views

Let $P\in \Bbb{Z}[X]$ be a polynomial with degree $d>1$. It is conjectured that for all such $P$, their range for integer inputs $R_P:=P(\Bbb{Z})$ has finite intersection with the set of factorials ...
Zach Hunter's user avatar
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4 votes
4 answers
723 views

I've asked two years ago a post on Mathematics Stack Exchange, were provided two excellent answers. I'm asking on MathOverflow in the hope that some professor can to expand/improve (if it is possible) ...
user142929's user avatar
4 votes
1 answer
170 views

Denote by $f(n)$ the maximal number of distinct divisors of $k$ integer numbers $1\leq a_1<a_2<\ldots<a_k\leq n$, where $k$ is not fixed and $a_1+\ldots+a_k\leq n$. I'm interested in the ...
Alexey Staroletov's user avatar
1 vote
1 answer
220 views

I'm curious about if the following question is in the literature or what work can be done about it. Denote the number of distinct primes dividing an odd perfect number $N$ with the arithmetic function ...
user142929's user avatar
0 votes
1 answer
277 views

Let $N = p^k m^2$ be an odd perfect number with special prime $p$ satisfying $p \equiv k \equiv 1 \pmod 4$ and $\gcd(p,m)=1$. Descartes (1638), Frenicle (1657), and subsequently [Sorli (2003) - ...
Jose Arnaldo Bebita Dris's user avatar
3 votes
1 answer
271 views

In this post I consider the equation $$k\cdot x=y^2+z^2(x^2-2)-2\tag{1}$$ over odd integers $y\geq 1$ and $z\geq 1$, and over integers $k\geq 1$ and very large Mersenne exponents $x$ such that $x^2-2$ ...
user142929's user avatar
5 votes
1 answer
221 views

Let $D_n$ be the set of divisors of $n$. Does there always exists a $B\subseteq D_n$ such that $D_n = \{\gcd(ab,n) \mid a\leq \sqrt{n}, b\in B\}$ and $\sum_{b\in B} \frac{n}{b}=O(n)$?
Chao Xu's user avatar
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