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Questions tagged [computability-theory]

computable sets and functions, Turing degrees, c.e. degrees, models of computability, primitive recursion, oracle computation, models of computability, decision problems, undecidability, Turing jump, halting problem, notions of computable randomness, computable model theory, computable equivalence relation theory, arithmetic and hyperarithmetic hierarchy, infinitary computability, $\alpha$-recursion, complexity theory.

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This is related to the second part of this old question of mine. For $A\subseteq\mathbb{N}$ let $\mathfrak{N}_A=(\mathbb{N};0,1,+,A)$ be the expansion of Presburger arithmetic with (a predicate naming)...
Noah Schweber's user avatar
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The notion of an effectively axiomatised theory is based on computing abilities of a Turing machine. For instance, the wffs and proofs are required to be decidable, the theorems are required to be ...
Ryder Rude's user avatar
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Say that a forcing notion $\mathbb{P}$ is slow iff there is some $f:\mathbb{R}\rightarrow\mathbb{R}$ (in $V$) such that for every $\mathbb{P}$-name for a real, $\nu$, we have $\Vdash_\mathbb{P}\exists ...
Noah Schweber's user avatar
16 votes
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Below work in $\mathsf{ZFC+CH}$ for simplicity. Say that a (set) forcing notion $\mathbb{P}$ captures a map $f:\mathbb{R}\rightarrow\mathbb{R}$ iff there is some $\mathbb{P}$-name for a real $\nu$ ...
Noah Schweber's user avatar
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For $n\in\omega$ and $x$ a real let $C_n^x$ be the canonical $\Pi^1_n(x)$-complete set. E.g. $C_1^x=\mathcal{O}^x$, etc. I recall seeing long ago the fact that, assuming large cardinals (precisely: ...
Noah Schweber's user avatar
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If $X'$ computes $\mathcal{O}^{Y}$ must $X$ compute $Y$? If not is there a function $\Gamma$ which guarantees that if $X'$ computes $\Gamma(Y)$ then $X$ computes $Y$? It is easy enough to see that ...
Peter Gerdes's user avatar
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I was reading last evening a paper which talked a bit about behaviors on cones and I know for a fact that Martin's conjecture is one of the most active areas in computability and that it was settled ...
H.C Manu's user avatar
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Take any desired consistent c.e. theory $T$ asserting the basic facts of arithmetic such that $T$ can formalize the operation of Turing machines. There is some Turing machine program $p$ and input $n$ ...
Jack Edward Tisdell's user avatar
11 votes
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Definitions: If $M,C\subseteq\mathbb{N}$, let us say that a function $f\colon\mathbb{N}\to\mathbb{N}$ is an encoding of $M$ by $C$ when $f^{-1}(C) = M$ (i.e., for all $m\in\mathbb{N}$ we have $m\in M$...
Gro-Tsen's user avatar
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TL;DR: I define a three-player game (Arthur, Nimue, Merlin) where Nimue is shown a hidden bit $b$ chosen by Merlin and tries to communicate it to her ally Arthur, but Arthur must act computably while ...
Gro-Tsen's user avatar
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What are some good examples of problems which are complete for higher levels of the arithmetic hierarchy and which come from parts of mathematics outside of logic? By "complete for higher levels ...
Patrick Lutz's user avatar
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Do all the Turing degrees agree, in a definable (hyperarithmetic? arithmetic?) way, on an ordering of their representatives? I'll make this precise below but roughly the question is whether there is ...
Peter Gerdes's user avatar
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One consequence of Martin's conjecture is that if $f$ is a Turing degree invariant Borel function from $2^\omega$ to $2^\omega$ then there is a pointed perfect tree $T$ such that either $f$ is ...
Peter Gerdes's user avatar
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1 answer
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We call a binary sequence $s:\mathbb{N}\to\{0,1\}$ supernormal if for every injective, increasing and computable function $\iota:\mathbb{N}\to\mathbb{N}$, the binary sequence $s\circ\iota:\mathbb{N}\...
Dominic van der Zypen's user avatar
4 votes
1 answer
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There is this theorem I found in an article by Stephen, Yang and Yu due to Ershov(theorem 4.6 in http://maths.nju.edu.cn/~yuliang/ssyy.pdf) which says the following: (a) There exists an unbounded path ...
H.C Manu's user avatar
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13 votes
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This is tangentially related to this old question of mine. Say that a clean well-ordering is a computable well-ordering $\triangleleft$ of $\mathbb{N}$ such that the following additional data is ...
Noah Schweber's user avatar
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230 views

In what follows, $A, B$ will denote subsets of $\mathbb{N}^{\mathbb{N}}$, i.e., sets of total functions $\mathbb{N} \to \mathbb{N}$ (maybe assume them to be inhabited to avoid any headaches about the ...
Gro-Tsen's user avatar
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Some people already have asked questions concerning Sy Friedman's results: (1) For $x\in\mathbb{R}$ if every $x$-admissible ordinals are stable, then $0^\#\in L[x]$. (2) There can be, by a class-...
Hiroshi Fujita's user avatar
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1 answer
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I am quoting a paragraph from the second paper of Jockush and Shore on REA operators about generating the REA sets recursively via a system of notations: "We can then associate $R$-sets with this ...
H.C Manu's user avatar
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21 votes
1 answer
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In the book, Chi Tat Chong and Liang Yu, "Recursion Theory, Computational Aspects of Definability", De Gruyter 2015, Exercise 5.3.5 (p.98) quotes S.G.Simpson's result as follows: If there ...
Hiroshi Fujita's user avatar
17 votes
0 answers
740 views

Consider the sequence $$a_n:=\min_{\substack{A\subseteq\mathbb{Z}\\|A|=n}}|(A+A)\cup (A\cdot A)|.$$ This is A263996 in OEIS. (Actually, they restrict to $\mathbb{N}$, but it makes little difference to ...
Dustin G. Mixon's user avatar
16 votes
1 answer
723 views

This question is inspired by a recent Quanta article, which explained that in order to compute BB(6), it is necessary to solve an "antihydra problem" which is somewhat similar to the ...
Gabe K's user avatar
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3 votes
1 answer
176 views

Are there any non-standard models of RCA$_0$ such that every subset of $\omega$ appears as a restriction of a set in the second-order part to it's standard initial segment? In other words, does ...
Peter Gerdes's user avatar
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6 votes
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130 views

It is a result of Levin and (independently?) Kautz that if $X \in 2^\omega$ is 1-ML random relative to a computable measure $\mu$ the either $X$ is computable (it is an atom of $\mu$) or $X$ is Turing ...
Peter Gerdes's user avatar
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20 votes
3 answers
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In what follows, we let $T$ be a consistent, recursively axiomatizable theory that includes $\mathsf{PA}$ (Peano arithmetic). Definition: Let us say that the theory $T$ is creative when the set of ...
Gro-Tsen's user avatar
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2 votes
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Is choice needed to construct a free ultrafilter on the boolean algebra of computable sets? Inspiration I ask this purely out of curiosity and because it's a natural follow-up question to GVT's ...
Keith J. Bauer's user avatar
8 votes
2 answers
586 views

As in the title: let $\mathfrak{F}$ be a filter on $\mathbb{N}$ such that, for every computable set $A\subseteq \mathbb{N}$, either $A\in\mathfrak{F}$ or $\mathbb{N}\setminus A\in\mathfrak{F}$; is $\...
GVT's user avatar
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8 votes
3 answers
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Is it known to be consistent with ZFC for there to exist a Turing degree invariant projective set which neither contains nor is disjoint from a cone? What about in $L$, i.e., is it known that (the ...
Peter Gerdes's user avatar
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11 votes
1 answer
522 views

Let $\mathcal{U}$ be a free ultrafilter on $\mathbb{N}$. Given a computable function $f : \mathbb{N} \to \mathbb{N}$ such that $f(0) < f(1) < \cdots$, suppose we have a set $S(f)$ such that $|\{...
BPP's user avatar
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5 votes
0 answers
324 views

Lets consider two entities with different hyper-computational strength. Entity A is able to comprehend the whole continuum and hence it decides every arithmetic sentence and, assuming Projective ...
Pan Mrož's user avatar
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3 answers
401 views

Let: $\mathcal{K}_1$ be the first Kleene algebra, meaning $\mathbb{N}$ endowed with the partial operation $(p,n) \mapsto p\bullet n := \varphi_p(n)$ where $\varphi$ is the $p$-th partial computable ...
Gro-Tsen's user avatar
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3 votes
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The least recursively inaccessible ordinal $I$, is, intuitively, the supremum of the ordinals that come from "recursively" iterating the function $\alpha\mapsto\omega^{CK}_\alpha$. For an ...
Reflecting_Ordinal's user avatar
8 votes
0 answers
196 views

I am aware that the structure $(\mathbb{R},+,\cdot,<,\sin)$ is extremely wild. Indeed, since the natural numbers are definable in such structure, one can define, via first-order formulas without ...
Lucio Tanzini's user avatar
2 votes
0 answers
186 views

What do "Realizability of the axiom of choice in HOL" and "Realizability and the Axiom of Choice" mean when they claim they realize a non extensional version of $\sf AC$? Can they ...
Ember Edison's user avatar
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3 votes
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I am going through Jockush and Shore's paper on transfinite pseudo-jump operators from '84 and in it's introduction it is mentioned that the transfinite pseudo-jump operators are properly contained in ...
H.C Manu's user avatar
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18 votes
1 answer
851 views

Basic background: A hydra is a finite rooted tree (with the root usually drawn at the bottom). The leaves of the hydra are called heads. Hercules is engaged in a battle with the hydra. At each step of ...
Monte_carlo's user avatar
7 votes
1 answer
286 views

I am currently reading a subsection of Chong & Yu(2010), specifically section 11.2 which is dedicated to a theorem of Harrington and I quote: Theorem 11.2.1 For any ordinal $ \beta < \omega_{\...
H.C Manu's user avatar
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2 votes
2 answers
577 views

Suppose I want to uniformly represent computation in an infinite series, what is the smallest/most natural set of operations I need to express the $n$-th term that allows me to capture arbitrary ...
Peter Gerdes's user avatar
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2 votes
0 answers
100 views

All trees discussed here are fully pruned subsets of $\omega^{< \omega}$ closed under substring and containing $\langle \rangle$ (the empty string). Definition: T is completely $\omega$ branching ...
Peter Gerdes's user avatar
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-2 votes
1 answer
569 views

Basic setups: A Turing machine M operates on a doubly infinite tape. The tape is divided into cells. Each cell can hold either a 0 or a 1 (meaning, we will consider only TM’s with two symbols). The ...
Monte_carlo's user avatar
7 votes
1 answer
380 views

By this post I would like to ask the Community to kindly share information about existing problems on explicit embeddings of recursive groups into finitely presented groups. Every recursive group (i.e....
V. Mikaelian's user avatar
6 votes
0 answers
268 views

Goodstein's "Recursive Number Theory" (1957) presents a "logic-free" version of primitive recursive arithmetic: all statements in the logic are equalities of expressions involving ...
TomKern's user avatar
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3 votes
1 answer
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The following questions may be well-known in which case I would be happy to be directed to a published reference. Q1. Let $d \in 2^{\omega}$ be noncomputable and $A \subseteq \omega$. For each $C \...
Hello World's user avatar
8 votes
1 answer
507 views

Definition: “The” first Kleene algebra $\mathcal{K}_1$ is the set $\mathbb{N}$ of natural numbers endowed with the partial operation $(p,n) \mapsto p\bullet n := \varphi_p(n)$ where $\varphi_p$ is the ...
Gro-Tsen's user avatar
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5 votes
1 answer
484 views

$\newcommand\ZF{\mathrm{ZF}}\newcommand\KPU{\mathrm{KPU}}$I am trying to read Barwise's Admissible Sets and Structures and I am just starting, so pardon if I may be missing something basic here. The ...
Link L's user avatar
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10 votes
0 answers
323 views

I begin by recalling Noether's problem over $\mathbb{Q}$: Let $G$ be a finite group that act faithfully by field automorphisms on $\mathbb{Q}(x_1,\ldots,x_n)$, with the action on $\mathbb{Q}$ trivial. ...
jg1896's user avatar
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10 votes
2 answers
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Let IPL mean the intuitionist propositional calculus. One can add a great diversity of axiom schemas to obtain intermediate logics between IPL and CPL, where CPL is the classical propositional ...
Ândson josé's user avatar
7 votes
1 answer
342 views

I am looking for a topos that describes realizability by Turing machines with access to a “variable oracle”. I think the construction I want is this. Start with Baire space $\mathcal{N} := \mathbb{N}^...
Gro-Tsen's user avatar
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4 votes
1 answer
266 views

There is this paper by Khan and Miller titled "FORCING WITH BUSHY TREES"(here is a free source:https://people.math.wisc.edu/~jsmiller8/Papers/bushy_trees.pdf) in which the main results ...
H.C Manu's user avatar
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9 votes
1 answer
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It is classical that the homeomorphism problem for finite simplicial complexes is unsolvable. All the sources I know for this actually prove something slightly different: Theorem: For $n \geq 5$, ...
Anonymous Math Person's user avatar

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