2
$\begingroup$

Have You seen these result as follows before?

  • In Figure 1: $AA'=BB'=tAB$; $CC'=DD'=tCD$, where t is real number then $ABCD$ is a cyclic quadrilateral iff $A'B'C'D'$ is a cyclic quadrilateral.

  • In the Figure 2: $B_a, C_a, C_b, A_b, A_c, B_c$ lie on a conic.

See also:

enter image description here

$\endgroup$
2
  • $\begingroup$ Power of a point might be used to prove it. $\endgroup$ Commented Aug 12, 2024 at 1:35
  • $\begingroup$ Yes, proof is easy $\endgroup$ Commented Aug 12, 2024 at 1:58

0

You must log in to answer this question.

Start asking to get answers

Find the answer to your question by asking.

Ask question

Explore related questions

See similar questions with these tags.