2
$\begingroup$

Let $G$ be $p$-adic group and let $G \rightarrow GL(V)$ be a representation. For example, $V$ is a quadratic $\mathbb{Q}_p$-space and $G$ is the associated orthogonal group.

Take a point $v \in V$, let $H \subset G$ be its stabilizer and assume $X = H \backslash G = G \cdot v \subset V$ is a closed subvariety. To continue with the example, $H = O(v^{\perp})$.

I consider the indicator function of (the image via the projection $G \rightarrow H \backslash G$ of) $H \cdot K$, for some compact open subgroup $K$, and I want to extend this indicator function to a locally constant smooth function on $V$.

Is it somehow possible ? Do you know of any work that addresses similar questions ?

$\endgroup$
2
  • 2
    $\begingroup$ It's a bit unclear to me when you are working with rational points, and when not. For example, do you want to regard $X$ as $G(\mathbb Q_p)\cdot v$ or $(G\cdot v)(\mathbb Q_p)$, which can be larger? Is your $p$-adic field always of characteristic $0$, or might it be, say, $\mathbb F_p((t))$? But, most importantly, regardless of these subtleties, I don't understand the question: by almost any interpretation, $H\backslash H\cdot K$ is compact open in the analytic topology, so its indicator is already locally constant (which, to me, in this context is what smooth means). What is missing? $\endgroup$ Commented Jul 4, 2024 at 13:57
  • 1
    $\begingroup$ Yes sorry I am working with fields of characteristic $0$ and I meant $(G \cdot v)(\mathbb{Q}_p)$. I'm looking for a locally constant and smooth function $f : V \rightarrow \mathbb{C}$ whose restriction to $G \cdot v$ (which may be viewed as a function on $H \backslash G$) is the indicator function of $H \backslash H \cdot K$. $\endgroup$ Commented Jul 4, 2024 at 14:29

1 Answer 1

3
$\begingroup$

Since $H^1(\mathbb Q_p, H)$ is finite and each fibre of $(G\cdot v)(\mathbb Q_p) \to H^1(\mathbb Q_p, H)$ is closed, we have that the fibre $G(\mathbb Q_p)\cdot v$ over the trivial cohomology class is open (as well as closed). Therefore, $G(\mathbb Q_p) \to (G\cdot v)(\mathbb Q_p)$ is an open map, so $K\cdot v$ is an analytically open subset of $(G\cdot v)(\mathbb Q_p)$.

Since $G\cdot v$ is a closed subvariety of $V$, we have that the analytic topology on $(G\cdot v)(\mathbb Q_p)$ is the subspace topology coming from the analytic topology on $V(\mathbb Q_p)$. Thus $K\cdot v$ is of the form $U \cap (G\cdot v)(\mathbb Q_p)$ for some analytically open subset $U$ of $V(\mathbb Q_p)$. Since the compact, open subsets of $V(\mathbb Q_p)$ form a basis for its topology, we can write $U$ as a union of compact, open subsets of $V(\mathbb Q_p)$. Since $K\cdot v$ is compact, finitely many of these compact, open subsets of $V$ suffice to cover it. Their union is compact, open, and still intersects $(G\cdot v)(\mathbb Q_p)$ in $K\cdot v$, so its indicator function is a smooth extension of the indicator function of $K\cdot v$.

$\endgroup$
0

You must log in to answer this question.

Start asking to get answers

Find the answer to your question by asking.

Ask question

Explore related questions

See similar questions with these tags.