0
$\begingroup$

I have a sequence of matrices $\lbrace A_i \rbrace_{i=1}^N$ and I want to select a column from each of these matrices so that the following sum is minimized:

$\sum_{i=1}^N || A_{i} \vec{x_{i}}- A_{i+1} \vec{x}_{i+1} ||_2^2$

$\vec{x}_i$ is a binary vector which selects a column of $A_i$. Formally: $x_{ij} \in \lbrace 0,1 \rbrace$ for $\forall i, j$ and $\sum_j x_{ij} = 1$ for $\forall i$.

How can I tackle this problem? Any hints or resources?

$\endgroup$

1 Answer 1

1
$\begingroup$

I think I found a solution using Dijkstra's shortest path algorithm. I would appreciate if anybody could check my solution.

Construct a graph as follows:

  1. Create a starting node $s$ and connect it to each column of $A_1$. The cost of these connections are all the same and equal to some arbitrary constant.

  2. Create a terminal node $t$ and connect it to each column of $A_N$. The cost of these connections are all the same and equal to some arbitrary constant.

  3. Connect the $j^{th}$ column of $A_i$ to the $k^{th}$ column of $A_{i+1}$ with a cost of $|| A_i \vec{y_i} - A_{i+1}\vec{y}_{i+1}||_2^2$ where $\vec{y_i}$ is all zeros except its $j^{th}$ element, and $\vec{y}_{i+1}$ is all zeros except its $k^{th}$ element.

  4. Compute the shortest path between $s$ and $t$. Then, it is trivial to determine $\vec{x_i}$s from the selected nodes in the solution.

$\endgroup$
1
  • $\begingroup$ I checked - it's correct. $\endgroup$ Commented Oct 25, 2010 at 18:28

You must log in to answer this question.

Start asking to get answers

Find the answer to your question by asking.

Ask question

Explore related questions

See similar questions with these tags.