The function’s name can be used to call the function from inside the function itself. That can be useful for recursive functions.

var thingsToDoToday = function flyToTheMoon() {
if(!onTheMoon)
flyToTheMoon();
else
alert(“One small step for a man..”);
}
thingsToDoToday();

It can also useful for debugging because you can see the function’s name in a call stack. Anonymous functions generally all look the same in the call stack. If you have a nasty debugging situation, sometimes giving names to the functions you are interested in can make things clearer.

var name = “foo”;
var customAction = function(x, y) {
print(“x+y=” + (x + y));
};

//implement it
var func = new Function(“action”, “return function ” + name + “(x,y){ print(action.toString());action(x,y) };”)(customAction);

//test it
func(1, 2);
print(func.toString());

customAction = {};
func(1, 2);
print(func.toString());
print(customAction);

// is name useful ??

var f1 = function fun1(x, y) {
return (x + y)
};
print(f1(1, 2));
try {
print(fun1(1, 2))
} catch (er) {
print(er.message)
};

print(f1.name);
oputput:
0: function (x, y) { print(“x+y=” + (x + y)); }
1: x+y=3
2: function foo(x,y){ print(action.toString());action(x,y) }
3: function (x, y) { print(“x+y=” + (x + y)); }
4: x+y=3
5: function foo(x,y){ print(action.toString());action(x,y) }
6: [object Object]
7: 3
8: fun1 is not defined
9: fun1

I found your page while I was looking for help with my requirement.

In my case, I want to return a value from the dynamic function

Pasted the code below, the custom function is getting executed but am getting ‘undefined’ for ‘returned’. Would you be able to help with this?

Thanks

var customFunction = function (name, data) {

return ‘something’;

};

var returned = null;

returned = func(e, results[e]);

console.log(returned);

if(returned){

group._currentData= returned;

}