@@ -1150,25 +1150,16 @@ audioop_ratecv(PyObject *self, PyObject *args)
11501150 ceiling(len*outrate/inrate) output frames, and each frame
11511151 requires bytes_per_frame bytes. Computing this
11521152 without spurious overflow is the challenge; we can
1153- settle for a reasonable upper bound, though. */
1154- int ceiling ; /* the number of output frames */
1155- int nbytes ; /* the number of output bytes needed */
1156- int q = len / inrate ;
1157- /* Now len = q * inrate + r exactly (with r = len % inrate),
1158- and this is less than q * inrate + inrate = (q+1)*inrate.
1159- So a reasonable upper bound on len*outrate/inrate is
1160- ((q+1)*inrate)*outrate/inrate =
1161- (q+1)*outrate.
1162- */
1163- ceiling = (q + 1 ) * outrate ;
1164- nbytes = ceiling * bytes_per_frame ;
1165- /* See whether anything overflowed; if not, get the space. */
1166- if (q + 1 < 0 ||
1167- ceiling / outrate != q + 1 ||
1168- nbytes / bytes_per_frame != ceiling )
1153+ settle for a reasonable upper bound, though, in this
1154+ case ceiling(len/inrate) * outrate. */
1155+
1156+ /* compute ceiling(len/inrate) without overflow */
1157+ int q = len > 0 ? 1 + (len - 1 ) / inrate : 0 ;
1158+ if (outrate > INT_MAX / q / bytes_per_frame )
11691159 str = NULL ;
11701160 else
1171- str = PyString_FromStringAndSize (NULL , nbytes );
1161+ str = PyString_FromStringAndSize (NULL ,
1162+ q * outrate * bytes_per_frame );
11721163
11731164 if (str == NULL ) {
11741165 PyErr_SetString (PyExc_MemoryError ,
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