Should not use stdout=PIPE or stderr=PIPE with subprocess.call() [...] the child process may block

bbigras · bbigras · commit 392117d90b22 · 2012-04-15T19:35:49.000-04:00
See : http://docs.python.org/library/subprocess.html#using-the-subprocess-module fixes kivy#29
diff --git a/src/build.py b/src/build.py
@@ -75,8 +75,7 @@ def compile_dir(dfn):
     '''
 
     # -OO = strip docstrings
-    subprocess.call([PYTHON,'-OO','-m','compileall','-f', dfn],
-            stdout=subprocess.PIPE, stderr=subprocess.PIPE)
+    subprocess.call([PYTHON,'-OO','-m','compileall','-f', dfn])
 
 def is_blacklist(name):
     for pattern in BLACKLIST_PATTERNS:
