int ia[5] = {1, 2, 3, 4, 5};

vector<int> iv(ia, ia + 5);

// 0+1+2+3...

cout << accumulate(iv.begin(), iv.end(), 0) << endl;

// 0-1-2-3

cout << accumulate(iv.begin(), iv.end(), 0, minus<int>()) << endl;

// 10 + 1*1 + 2*2 + ...

cout << inner_product(iv.begin(), iv.end(), iv.begin(), 10) << endl;

// 10 - 1+1 - 2+2 - ...

cout << inner_product(iv.begin(), iv.end(), iv.begin(), 10,

minus<int>(), plus<int>()) << endl;

// 将迭代器绑定到cout，作为输出用

ostream_iterator<int> oite(cout, " ");

// 1 3 6 10 15 累计和

partial_sum(iv.begin(), iv.end(), oite);

cout << endl;

// 1 -1 -4 -8 -13 累计差

partial_sum(iv.begin(), iv.end(), oite, minus<int>());

cout << endl;

// 1 1 1 1 1 new #n = #n - #n-1

adjacent_difference(iv.begin(), iv.end(), oite);

cout << endl;

// 1 3 5 7 9 new #n = op(#n, #n-1)

adjacent_difference(iv.begin(), iv.end(), oite, plus<int>());

cout << endl;

// mingw c++ 中stl没有power实现

// cout << power(10, 3) << endl;

// cout << power(10, 3, plus<int>()) << endl;

int n = 3;

iota(iv.begin(), iv.end(), n); // 填入n, n+1, n+2

for (int i = 0; i < iv.size(); ++i)

cout << iv[i] << ' ';

}