acpt: add scenario for _ParaStyle.paragraph_format

Steve Canny · Steve Canny · commit 8b5a221adbce · 2015-02-08T00:01:42.000-08:00
diff --git a/features/steps/styles.py b/features/steps/styles.py
@@ -10,6 +10,7 @@
 from docx.enum.style import WD_STYLE_TYPE
 from docx.styles.styles import Styles
 from docx.styles.style import BaseStyle
+from docx.text.paragraph import ParagraphFormat
 from docx.text.run import Font
 
 from helpers import test_docx
@@ -186,6 +187,14 @@ def then_style_name_is_the_which_name(context, which):
     assert style.name == expected_name
 
 
+@then('style.paragraph_format is the ParagraphFormat object for the style')
+def then_style_paragraph_format_is_the_ParagraphFormat_object(context):
+    style = context.style
+    paragraph_format = style.paragraph_format
+    assert isinstance(paragraph_format, ParagraphFormat)
+    assert paragraph_format.element is style.element
+
+
 @then('style.style_id is the {which} style id')
 def then_style_style_id_is_the_which_style_id(context, which):
     expected_style_id = {
diff --git a/features/sty-access-parfmt.feature b/features/sty-access-parfmt.feature
@@ -0,0 +1,15 @@
+Feature: Access style paragraph format
+  In order to discover or change the paragraph formatting of a style
+  As a developer using python-docx
+  I need access to the paragraph format of a style
+
+
+  @wip
+  Scenario Outline: Get style paragraph format
+    Given a style of type <style-type>
+     Then style.paragraph_format is the ParagraphFormat object for the style
+
+    Examples: Style types
+      | style-type              |
+      | WD_STYLE_TYPE.PARAGRAPH |
+      | WD_STYLE_TYPE.TABLE     |
