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gen.po
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62 lines (53 loc) · 1.82 KB
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# SOME DESCRIPTIVE TITLE.
# Copyright (C) 2001-2017, Python Software Foundation
# This file is distributed under the same license as the Python package.
# FIRST AUTHOR <EMAIL@ADDRESS>, 2017.
#
#, fuzzy
msgid ""
msgstr ""
"Project-Id-Version: Python 3.6\n"
"Report-Msgid-Bugs-To: \n"
"POT-Creation-Date: 2017-11-26 18:49+0900\n"
"PO-Revision-Date: YEAR-MO-DA HO:MI+ZONE\n"
"Last-Translator: FULL NAME <EMAIL@ADDRESS>\n"
"Language-Team: LANGUAGE <LL@li.org>\n"
"MIME-Version: 1.0\n"
"Content-Type: text/plain; charset=utf-8\n"
"Content-Transfer-Encoding: 8bit\n"
"Generated-By: Babel 2.5.1\n"
#: ../Doc/c-api/gen.rst:6
msgid "Generator Objects"
msgstr ""
#: ../Doc/c-api/gen.rst:8
msgid ""
"Generator objects are what Python uses to implement generator iterators. "
"They are normally created by iterating over a function that yields "
"values, rather than explicitly calling :c:func:`PyGen_New` or "
":c:func:`PyGen_NewWithQualName`."
msgstr ""
#: ../Doc/c-api/gen.rst:15
msgid "The C structure used for generator objects."
msgstr ""
#: ../Doc/c-api/gen.rst:20
msgid "The type object corresponding to generator objects."
msgstr ""
#: ../Doc/c-api/gen.rst:25
msgid "Return true if *ob* is a generator object; *ob* must not be *NULL*."
msgstr ""
#: ../Doc/c-api/gen.rst:30
msgid "Return true if *ob*'s type is *PyGen_Type*; *ob* must not be *NULL*."
msgstr ""
#: ../Doc/c-api/gen.rst:35
msgid ""
"Create and return a new generator object based on the *frame* object. A "
"reference to *frame* is stolen by this function. The argument must not be"
" *NULL*."
msgstr ""
#: ../Doc/c-api/gen.rst:41
msgid ""
"Create and return a new generator object based on the *frame* object, "
"with ``__name__`` and ``__qualname__`` set to *name* and *qualname*. A "
"reference to *frame* is stolen by this function. The *frame* argument "
"must not be *NULL*."
msgstr ""