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program18.java
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73 lines (50 loc) · 1.78 KB
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/*
66. Plus One
Easy
7.1K
4.9K
Companies
You are given a large integer represented as an integer array digits, where each digits[i] is the ith digit of the integer. The digits are ordered from most significant to least significant in left-to-right order. The large integer does not contain any leading 0's.
Increment the large integer by one and return the resulting array of digits.
Example 1:
Input: digits = [1,2,3]
Output: [1,2,4]
Explanation: The array represents the integer 123.
Incrementing by one gives 123 + 1 = 124.
Thus, the result should be [1,2,4].
Example 2:
Input: digits = [4,3,2,1]
Output: [4,3,2,2]
Explanation: The array represents the integer 4321.
Incrementing by one gives 4321 + 1 = 4322.
Thus, the result should be [4,3,2,2].
Example 3:
Input: digits = [9]
Output: [1,0]
Explanation: The array represents the integer 9.
Incrementing by one gives 9 + 1 = 10.
Thus, the result should be [1,0].
*/
package LeetCode;
public class program18 {
static int[] plusOne(int[] digits) {
for (int i = digits.length - 1; i >= 0; i--) {
if (digits[i] < 9) {
digits[i]++;
return digits;
}
digits[i] = 0;
}
digits = new int[digits.length + 1];
digits[0] = 1;
return digits;
}
public static void main(String[] args) {
int[] digits ={};
int a[] = new int[digits.length+1];
a = plusOne(digits);
for(int i=0;i<a.length;i++){
System.out.print(a[i]+" ");
}
}
}